Graph C is the correct option.
If you drew a straight line (mostly) connecting the points, it would be linear. A relationship is linear if one variable, in this case, x, increases by approximately the same rate as the other variables, in this case y.
If you drew lines connecting points on the other graphs, they wouldn’t resemble a straight line, therefore, they aren’t linear.
Answer:
Step-by-step explanation:
1
Answer:
6x^2 +8x
Step-by-step explanation:
(12x^3 -14x^2 -40x) / (2x-5)
Factor the numerator by factoring out the greatest common factor
2x( 6x^2 -7x-20) / (2x-5)
Factor inside the parentheses
2x (3x+4)(2x-5)/ (2x-5)
Cancel like terms
2x( 3x+4)
Distribute
6x^2 +8x
2x+ 1 = 3x - 1 ;
1 + 1 = 3x - 2x ;
2 = x ;
x = 2 ;
Then, y = 2x2 + 1 = 5 ;
We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4