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2 years ago

Please can someone tell me the defenitions of each of these terms?

Mathematics

1 answer:

Xelga [282]2 years ago

5 0

A fee charged based on the total cost of things you buy. It is collected by the seller and added onto the price of the things bought. It's based on a percent set by the government.
A partial discount or refund given on a purchased item
Taxes paid by employees to federal and state government. Collected or withheld from one's paycheck.
The total amount of an employee's earnings before deductions are taken out (aka Total Pay), and may include overtime pay
The pay you get after taxes and the deductions. You subtract your gross pay by federal tax, social security, etc.

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Graph the line with slope 1/5 and y-intercept-2

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You want to start at -2 on the y line wich is the vertical line then 1/5 is rise over run so you rise (go up) one and run ( go right)5

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2 years ago

Anna lives 9 blocks from school. How many blocks does she walk to school in 3 days

netineya [11]

Multiply 9 by 3

she walks 27 blocks in three days

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3 years ago

Read 2 more answers

Fill in the information in the table. The first is done for you

lisov135 [29]

Answer:

≥ closed dot

< open dot

≤ less than or equal to closed dot

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2 years ago

two lines intersect.One has gradient 4 and y-axis intercept 3. The other has gradient 6 and cuts the y-axis at (0,1). What is th

timurjin [86]

Answer:

(1, 7 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Then the equations of the 2 lines are

y = 4x + 3 → (1)

y = 6x + 1 → (2)

Substitute y = 6x + 1 into (1)

6x + 1 = 4x + 3 ( subtract 4x from both sides )

2x + 1 = 3 ( subtract 1 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting into (1)

y = 4(1) + 3 = 4 + 3 = 7

Point of intersection = (1, 7 )

5 0

3 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: