$(x^3-8x^2+19x-9)\div(x-4)=x^2-4x+3\\\underline{-x^3+4x^2}\\=-4x^2+19x\\\underline{\ \ \ \ \ 4x^2-16x}\\.\ \ \ =3x-9\\\underline{\ \ \ \ \ -3x+12}\\.\ \ \ \ \ =\ 3$

$x^3-8x^2+19x-9=(x^2-4x+3)(x-4)+3$

6 0

3 years ago

Trigonometry Problem Find the length of the missing side.

Vlad [161]

Answer:

x= 141.8179

Step-by-step explanation:

side a is 38, side b is 141.8179, side c is 146.8207

angle a is 15 angle b is 90 ancle c is 75

7 0

3 years ago

You can drive your car for 4.5 hours at the average speed of 70 miles per hour. how far did you go?

Zigmanuir [339]

Answer:

Step-by-step explanation:

28.5

3 0

3 years ago

Perform the operation. (9x2 + 6x – 7) + (-9x - 5) PLS HELP ASAP PLS

qaws [65]

Answer:

Step-by-step explanation:

(9x2 + 6x – 7) + (-9x - 5) = 21

6 0

2 years ago

Read 2 more answers