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Andreas93 [3]
3 years ago
14

Can any one please help me to do e and d please can anyone do it for me please

Mathematics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

d = 520 cm^3   e = 1717.66 cm^2

Step-by-step explanation:

d) The area of the face triangle is 40 and multiply that with the length, 13 to get 520.

e) The volume of the half circle is 190.85 and the volume of the cone is 1526.81 and add them

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Part 1 You will need to measure five different people. Record your measurements on a piece of paper. Using a tape measure or rul
Jlenok [28]

Answer:

Part 1 and 2:  

A. Forearm (in)        Foot (in)                      

Sarah   10                9

Sam   11.               10

Emma  8                  7

Mom   10                 9

Dad  11                 10  

B. M=9-7 over 8-10 the answer is 2 over 2.

 

C.  For every forearm the foot is one inch smaller.

Part 3:

A. 0.860(17)+3.302

B. Y=17.922. They are slightly different.  Keren’s has a greater rate.  I think the values are different because they have different origins.

C. Yes, because it is an important part for rate of change. Yes it is a function because there can’t be any exponents greater than 1, and its not a straight line if you plug it in.

Step-by-step explanation:

This is just an example dont you the names

8 0
3 years ago
find the point-slope equation of the line perpendicular to the line y=2x+5 passing through the point (1,4). (please include solu
pishuonlain [190]
First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?

well, notice, that equation is in slope-intercept form, thus   \bf y=\stackrel{slope}{2}x+5.

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{2\implies \stackrel{slope}{\cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
slope =  m\implies -\cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{1}{2}(x-1)
7 0
3 years ago
- (4x4- 2x' +7x²+2 x - 1)=(x+3)
Gnom [1K]

Answer:

No solution?

Step-by-step explanation:

Im confused, can you give more information.

4 0
3 years ago
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
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Which of the following represents the general term for the sequence 1, 3, 5, 7, 9, . . .? n
zalisa [80]

Answer:

Step-by-step explanation:

In the given sequence, the terms are increasing in arithmetic progression. The common difference, d between successive terms is 2

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 1

d = 2

Therefore, the expression for the general term for the sequence is

Tn = 1 + 2(n - 1)

3 0
3 years ago
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