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4 years ago

13

Jethro wants a swimming pool in his backyard, so he digs a rectangular hole with dimensions 40 feet long, 20 feet wide, and 5 fe

et deep. How many cubic feet of water will the pool hold?
65
8000
4000
40,000

1 answer:

Genrish500 [490]4 years ago

6 0

<span>4000 so the answer is C
Hope this helps</span>

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A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia

Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and irrespective of the order.

${n\choose k}=\frac{n!}{k!(n-k)!}$

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

$^{n}P_{k}=\frac{n!}{(n-k)!}$

In this case we need to select two different cards from a pack of 52 cards.

Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${52\choose 2}=\frac{52!}{2!(52-2)!}$

$=\frac{52\times 51\times 50!}{2!\times50!}\\=1326$

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

$^{n}P_{k}=\frac{n!}{(n-k)!}$

$^{52}P_{2}=\frac{52!}{(52-2)!}$

$=\frac{52\times 51\times 52!}{50!}$

$=52\times 51\\=2652$

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0

3 years ago

What is the difference between greatest common divisor and greatest common denominator ?

il63 [147K]

The greatest common factor (GCF) of a set of numbers is the largest factor that all the numbers share. For example, 12, 20, and 24 have two common factors: 2 and 4. The largest is 4, so we say that the GCF of 12, 20, and 24 is 4. GCF is often used to find common denominators

7 0

3 years ago

A decibel is a logarithmic unit that can be used to measure the intensity of a sound. The function y = 10logx gives the intensit

Anna007 [38]

Answer:

The sound intensity of a whisper is 333.3 times the reference intensity

Step-by-step explanation:

Given : The function $y = 10logx$ gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.

A whisper has a sound intensity of 30 decibels.

To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.

Solution :

Graph is attached which shows their intersection at (1000,30).

We can also verify by substituting value.

We have given that a whisper has a sound intensity of 30 decibels.

Therefore, y=30 , Let log base 10

$y = 10logx$

$30 = 10logx$

$\frac{30}{10} =logx$

$3=logx$

Logarithmic property $log_{x}b=a \Rightarrow b=x^a$

$x=10^3$

$x=1000$

The ratio of the intensity of the sound to a reference intensity is 1000 decibels

The sound intensity of a whisper is times the reference intensity is

$\frac{1000}{3}=333.33$

The sound intensity of a whisper is 333.3 times the reference intensity.

7 0

3 years ago

Read 2 more answers

134 rounds to the nearest tens

I am Lyosha [343]

Answer:130

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

12. The Opera is collecting monies in advance for ticket sales. The tickets cost $17.50 each.

Debora [2.8K]

Answer:

The number of tickets they have sold in advance are summed up with the following equation and solution:

Equation: $\frac{6842.50}{17.50}$ [the final answer should be in dollars]

Solution: The Opera sold 391 tickets in advance.

Step-by-step explanation:

First: Review some background information:

Let's see what the problem gives us to answer it. I'll bold out the important parts:

The Opera is collecting monies in advance for ticket sales. The tickets cost $17.50 each. If they have collected $6842.50 already, then how many tickets have they sold in advance?

We know how much the tickets cost and how much money they have earned from selling tickets, we can find out how much tickets they have sold.

Second: Solve the problem:

We can solve this problem using many ways, but I'm just going to pick one. We will use proportions to answer this. Now thoughts might be going through your head like this: What is this guy saying? What in the world is proportions? Well hopefully you learn from this example (Please don't take offense if you <em>do</em> know how to do proportions).

First we set up two fractions. One ticket costs $17.50, so we will use it to set up our first fraction: $\frac{1}{17.50}$ . We don't know how many tickets all together cost $6842.50 so we will use the variable: x. Now, we can set up our second fraction. x tickets costs $6842.50 so our second fraction will be: $\frac{x}{6842.50}$ . Now we must use cross multiplication. We multiply the numerator of the first fraction times the denominator of the second fraction, and then we multiply the denominator o the first fraction times the numerator of the second fraction. That's what we would do usually. But now, since we have a variable, we must use cross multiplication to solve for this variable. So we multiply the the numerator of the first fraction times the denominator of the other fraction and then we divide that answer times the denominator of the first fraction (You don't have to set it up like this).So let's solve this question:

$\frac{1}{17.50}$ $\frac{x}{6842.50}$

1 x 17.50 = 17.50

6842.50 ÷ 17.50 = 391

So our equation is 6842.50 ÷ 17.50, and our solution is 391 tickets

Topic: Proportions

6 0

3 years ago