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1 year ago

Item to ship 58 , items per case 6

Mathematics

2 answers:

9966 [12]1 year ago

6 0

Answer: 9 and 2/3 cases

Step-by-step explanation:

6 goes into 58 9 times to make 54 so makes 4 left over 4/6 simplified makes 2/3.

sineoko [7]1 year ago

5 0

10 cases

First we divide 58 items by 6 items per case to figure out how many cases we need. We get 9 cases with a remainder of 4 items. We need another case (bringing us up to a total of 10 cases) for the remaining items. Although 4 items does not completely fill a case, we cannot ship a fraction or part of a case, so we need to ship 10 cases.

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Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor

OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 110, \sigma = 0.15$

The proportion of infants with birth weights between 125 oz and 140 oz is

This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So

X = 140

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{140 - 110}{15}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 125

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 110}{15}$

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$Z = 1$ has a pvalue of 0.8413

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The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

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3 years ago

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The general vertex form is this:
v(x) = a (x-h)2 + k
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and a indicates the widening or shrinking of the function compared to another parabolic function. If a become bigger, the graph becomes narrower. If a becomes negative, the graph is reflected over the x-axis.

Comparing f(x) = x2 with g(x) = -3(x+6)2 + 48, we have the following transformations:
The graph is reflected over the x-axis
The graph is made narrower.
The graph is shifted 6 units to the left.
The graph is shifted 48 units up.

From the choices we only have:
<span>The graph of f(x) = x2 is made narrower</span>

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Answer:

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