Answer:
-390 mph
Step-by-step explanation:
Let a and b represent, respectively, the distances of A and B from the airport. The distance d between the planes is then given by the Pythagorean theorem as ...
d² = a² + b²
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
Solving for d', we get ...
d' = (a/d)a' +(b/d)b'
The value of d at the time of interest is ...
d = √(a² +b²) = √(30² +40²) = √2500 = 50
Then the rate of change of separation is ...
d' = (30/50)(-250 mph) +(40/50)(-300 mph) = (-150 -240) mph
d' = -390 mph
The distance between planes is decreasing at 390 miles per hour.
Your answer is B.
Flat fee is $250, so we cannot change this number.
585 - 250 = 335
335 (remaining cash) divided by 8 (price per student) = 41.875
Since we can't bring .8 of one student on the trip, we will round the number down to 41, because if we round up we will go over the budget of $585.
The maximum number of students a school can send is 41.
Answer:
x=3
Step-by-step explanation:
So -11 + 5 = -6, not -16.
Then divide -6 and -2x by -2 and x=3
Answer:
Y
=
−
5
x
−
26
y
=
x
/5
−
6
/5
Step-by-step explanation: