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liq [111]
1 year ago
12

In conducting a​ goodness-of-fit test, a requirement is that​ ________. Question content area bottom Part 1 A. the expected freq

uency must be at least five for each category B. the expected frequency must be at least ten for each category C. the observed frequency must be at least ten for each category D. the observed frequency must be at least five for each category
Mathematics
1 answer:
erica [24]1 year ago
7 0

In conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

<h3>What is a goodness of fit test?</h3>

In relation to the statistical model, the test tells how well it fits a set of observations.

The measures of the goodness of fit summarize the discrepancy between observed values and the values expected under the model in question.

Also, when conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

Therefore, the Option B is correct,

Read more about goodness of fit test

brainly.com/question/17438396

#SPJ1

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Hhhhhheeeeeeellllpppppppppplllllllllllllllllllllzzzzzzzzzzzzzzz
Fudgin [204]

Answer:

the answer is A. I believe

4 0
3 years ago
Please help me gow to this bro , im confused
Airida [17]
Ok so remember that a circle is 360 degrees and a line is 180 degrees
so

IKJ
ok so we see that we have a triangle
to find the internal angles (which add to 180)
we do, opposite angles are equal
JIK=59
also CJI+KJI=180 so 132+KJI=180, KJI=48
so
59+48+IKJ=180
73=IKJ




HIB
we can assume that AB is paralell to CD
so therefor IJK=HIB=48 (from previous question)

EIJ is adding to EIH to get 180
EIJ+59=180
EIJ=121

AIK=AIJ+JIK
JIK=59
AIJ=HIB=48
AIK=59+48=107


IKJ=73
HIB=48
EIJ=121
AIK=107
6 0
3 years ago
Do you know this I just need question number 6 I will give you a lot point or likes.
tatyana61 [14]

Answer: 2.117647

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
the length of a diagonal of a square field is 220 metres find the length of a side in metres and the area of the field in hectar
andre [41]

Answer:

Step-by-step explanation:

h^2=x^2+y^2, since this is a square x=y=s so

220^2=2s^2

2s^2=48400

s^2=24200

s=24200^(1/2)m (exact)

s=155.56m (rounded to nearest hundredth of a meter)

One hectare is equal to 10000m^2

A=24200m^2(h/10000m^2)

A=2.42 hectares

7 0
3 years ago
Can you help me with try these B?
Softa [21]
A. expanded, you get XxXxXxXxXxXxXxX over XxXxXxXxX
 b.XxXxX or X³
c. I would just cancel out the 5 Xs on the top line against the 5 Xs on the bottom, leaving X³.
6 0
3 years ago
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