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liq [111]
1 year ago
12

In conducting a​ goodness-of-fit test, a requirement is that​ ________. Question content area bottom Part 1 A. the expected freq

uency must be at least five for each category B. the expected frequency must be at least ten for each category C. the observed frequency must be at least ten for each category D. the observed frequency must be at least five for each category
Mathematics
1 answer:
erica [24]1 year ago
7 0

In conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

<h3>What is a goodness of fit test?</h3>

In relation to the statistical model, the test tells how well it fits a set of observations.

The measures of the goodness of fit summarize the discrepancy between observed values and the values expected under the model in question.

Also, when conducting a​ goodness of fit test, a requirement is that​ the expected frequency must be at least ten for each category.

Therefore, the Option B is correct,

Read more about goodness of fit test

brainly.com/question/17438396

#SPJ1

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Linear equations: w-3=15
motikmotik

Answer:

w = 18

Step-by-step explanation:

w-3=15

Add 3 to each side

w-3+3=15+3

w = 18

6 0
3 years ago
Read 2 more answers
If the product of two numbers is positive then the two numbers must both be positive true or false
Vlada [557]
False, a negetive and negetinve both equal positive

3 0
3 years ago
Sarah and Eva are swimming<br> use the ratio table to determine who is the faster swimmer
pentagon [3]
Sarahtime  (min)                    {3 }       5      12    17
distance (meters)        {75}      125   300  425

Eva time  (min)                     {2}    7      10    20
distance (meters)         {52}  182   260  520

 

Sarah:meters over min =75 over 3 = 25 over 1
25 meters per min


Eva :meters over min= 52 over 2 =26 over 1
 26 meters per min

eva is the faster swimming because 26 meters per min is faster then 25 meters per min .

i hope this help












6 0
3 years ago
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
3 years ago
The box for the cake in the shape of a cube with edges 9 inches in length .How many square inches of cardboard are needed to mak
Rasek [7]

Answer:

486²in

Step-by-step explanation:

9×9=81 (gives you one face of the cube)

81×6=486 (there are 6 faces on a cube)

5 0
3 years ago
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