The answer is C (289pi/6 mi2)
Dhudhejaiwiwiwiwjrjrjririr
Answer:
42.5 ft squared
Step-by-step explanation:
hope this helped brah
we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
<h3>What is the last digit of the product of all the numbers between 11 and 29?</h3>
Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.
Then we have the product:
P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28
Now, notice that there is a 20 there.
Any number times 20 will end with a zero, then:
P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)
Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
If you want to learn more about products:
brainly.com/question/10873737
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we have the function
y=f(x)=x^2
the domain is all real numbers -------> interval (-∞, +∞)
the vertex of the vertical parabola is the origin (0,0)
the parabola opens upward
the vertex is a minimum
so
the range is the interval [0, ∞)