To figure out the size of a rectangle that would represent the swimming pool, you will use the formula for volume of a rectangle or prism to solve for the area of the base.
V = Bh
1200 = 5B
B = 240 square feet
To get an area of 240 ft.², you could use the dimensions 10' x 24'. Another possibility would be 8' x 30'.
Answer:
458 turns/min ----- 13740/30 min
Step-by-step explanation:
3206/7 (min) = 458
458 x 30 (min) = 13740
Answer:
h(x) = (x +1.5)^2 -20.25
Step-by-step explanation:
We assume you want to rearrange h(x)= x^2 +3x -18.
Recognize the coefficient of x is 3. Add and subtract the square of half that. (3/2)^2 = 9/4 = 2.25
h(x) = (x^2 +3x +2.25) -18 -2.25
Now, write the expression in parentheses as a square, simplify the constant.
h(x) = (x +1.5)^2 -20.25 . . . . . . . . vertex form
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
Yes because 1500/60 = 25 which is the number of words per minute. He has 5 minutes to text so 25 x 5 = 125. In 5 minutes he can type 125 words