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lesantik [10]
1 year ago
5

Quick algebra 1 question for 10 points!

Mathematics
2 answers:
maksim [4K]1 year ago
5 0

Answer:

12.50 h = 2500.75

Step-by-step explanation:

We know from the question that the student earned $12.50 per hour.

Using this information, we can say that if the student worked for h hours, they would make a total of 12.50 × h dollars.

We also know that the total money they earned is $2500.75.

∴ Therefore, we can set up the following equation:

12.50 x h = 2500.75

From here, if we want to, we can find the number of hours worked by simply making h the subject of the equation and evaluating:

h=\frac{2500.75}{12.50}

= 200.6 Hours

NeTakaya1 year ago
4 0

Answer:

12.50h = 2500.75

Step-by-step explanation:

He earned $12.50 for 1 hour of work.

For 2 hours, he earned $12.50 × 2.

For 3 hours, he earned $12.50 × 3.

For h hours, he earned $12.50 × h which can be simply written as 12.50h

He earned altogether $2500.75, so 12.50h must equal 2500.75.

Answer: B 12.50h = 2500.75

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Dvinal [7]

Answer:3.14r^2

Step-by-step explanation:

if you are asking circumference then using circumference formula

circumference(c)=pi*r^2

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4 years ago
How in the heck do I do this?​
Fudgin [204]

The measure of a triangle is 180 degrees. In other words the sum of the angles of a triangle is 180 degrees

To solve for x set all of the expressions of angles equal to 180 and isolate x

11x - 3 + 7x + 5 + 13x - 8 = 180

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31x/31  = 186 / 31

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4 years ago
In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

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  m<ADG = 55

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   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

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xenn [34]

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