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sergey [27]
3 years ago
5

6x^2-x<2 solve, show your answer on a number line. State your answer in interval notation

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

6x^2-x

In order for the left side to be negative, we need either 3x-2>0 and 2x+1, or 3x-2 and 2x+1>0.

  • If 3x-2>0 and 2x+1, then x>\frac23 and x. There is no value of x that meets both conditions, so this case offers no solutions.
  • If 3x-2 and 2x+1>0, then x and x>-\frac12. This means any number x between -1/2 and 2/3 satisfies the inequality.

In interval notation, the solution set is

\boxed{-\dfrac12

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Can someone explain to me how to do this and give me the answer please?​
pantera1 [17]

Answer:

To find x, y, z, p and q, you need to know about the property of Rhombus.

13y + 10 = 7y + 16 (pair of equal opposite sides)

=> 6y = 6

=> y = 1

x = 7x + 16 (2 equal adjacent sides)

  = 7*1 + 16

  =23

z = 90 deg (angle between 2 diagonals)

q = 22 deg (isosceles triangle)

p = 90 - 22 = 68 deg (right triangle)

4 0
3 years ago
Find the slope of f(x)=5x-4
frosja888 [35]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
F(x)=4x^2+3x+13<br><br> Find f(1)
Pani-rosa [81]

Answer:

f(1) = 42

Step-by-step explanation:

Step 1: Switch all x out to 1 for f(1) which would look like this: f(1)=4(1)^2+3(1)+13

Step 2: You would then simplify it starting with 4(1)^2 which would equal 4 squared which equals 16.

Step 3: After simplifying you would have f(1)=16+3+13

Step 4: You then just add and get 42

Hope this helped :D

7 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: \frac{X-\mu}{\sigma}

Therefore

\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}

\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}

-1.5\leq z\leq 2.5

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0
3 years ago
Solve for x in the exponential equation 3^x=8​
KonstantinChe [14]

Answer:

x=1.89278

Step-by-step explanation:

change into a logmarith

log_3 8=x

use change of base formula

put in calculator

x= 1.89278

7 0
3 years ago
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