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anzhelika [568]
3 years ago
15

On the 1st of January 2014, Carol invested some money in a bank account. The account pays 2.5% compound interest per year. On th

e 1st of January 2015, Carol withdrew £1000 from the account. On the 1st of January 2016, she had £23 517.60 in the account. Work out how much Carol originally invested in the account?
Mathematics
1 answer:
cluponka [151]3 years ago
5 0
She started with x.
After 1 year, she had 1.025x.
She withdrew <span>£1000, so now she has 1.025x - 1000.
Then it earned interest for 1 year and ended up as </span>1.025(1.025x - 1000).
The actual amount of money was £23 517.60.
Therefore,

<span>1.025(1.025x - 1000) = 23517.60

1.025x - 1000 = 22 944

1.025x = 23 944

x = 23 360

Her original deposit was </span><span>£23 360</span>
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Answer:

The probability that there are 3 or less errors in 100 pages is 0.648.        

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In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.

For the given Poisson distribution the mean is p = 0.03 errors per page.

We have to find the probability that there are three or less errors in n = 100 pages.

Let us denote the number of errors in the book by the variable x.

Since there are on an average 0.03 errors per page we can say that

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Therefore the we find the probability that there are 3 or less errors on the page as

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   Using the formula for Poisson distribution for P(x = X ) = \frac{e^{-\lambda}\lambda^X}{X!}

Therefore P( X ≤ 3) = \frac{e^{-3} 3^0}{0!} + \frac{e^{-3} 3^1}{1!} + \frac{e^{-3} 3^2}{2!} + \frac{e^{-3} 3^3}{3!}

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7 0
3 years ago
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(y+2)(y+3)

(y*y)(y*3)(2*y)(2*3)

y^2+3y+2y+6

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Answer:

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Slope: 1

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