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1 year ago

KI's net income for 2021 is _____.

Mathematics

1 answer:

yKpoI14uk [10]1 year ago

6 0

The answer is d but I don’t for sure it might be a or c or b

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Given the function f(x)=|x+5|,find each of the following<br> F(10),f(-5),f(0)

stira [4]

I hope this helps you

x=10 f(10)=|10+5|=|15|=15

x=-5 f(-5)=|-5+5|=|0|=0

x=0 f(0)=|0+5|=|5|=5

3 0

2 years ago

Read 2 more answers

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

2 years ago

Read 2 more answers

"Complete the square" to convert the equation of each circle to graphing form. Identify the center and the radius.

Reil [10]

Answer:

The center is (-3,2) and the radius is r=2

Step-by-step explanation:

The general equation of the given circle is

$x^2+6x+y^2-4y=-9$

Add the square of half the coefficient of the linear terms to both sides of the equation to obtain;

$x^2+6x+3^2+y^2-4y+(-2)^2=-9+3^2+(-2)^2$

$x^2+6x+9+y^2-4y+4=-9+9+4$

$x^2+6x+9+y^2-4y+4=4$

The quadratic trinomials in x and y on the left side of the equations are perfect squares.

We factor to obtain;

$(x+3)^2+(y-2)^2=4$

$(x--3)^2+(y-2)^2=2^2$

Comparing to:

$(x-h)^2+(y-k)^2=r^2$

The center is (-3,2) and the radius is r=2

8 0

2 years ago

Convertir 0.16 en fracción

MrRa [10]

Answer:

4/25 en forma de fracción

Step-by-step explanation:

7 0

3 years ago

Selected-Response

maks197457 [2]

Answer: 6 pints

Step-by-step explanation:

32 times 3 in 96

so you must multiply 2 times 3

5 0

3 years ago