5220 is your answer
please can i have a brainliest
Hey there! :)
Answer:
y = 1/4x - 3.
Step-by-step explanation:
Use the slope-formula to find the slope of the line:
![m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B%5Ctext%7Brise%7D%7D%7B%5Ctext%7Brun%7D%7D%20%3D%20%5Cfrac%7By_2%20-%20y_1%7D%7Bx_2%20-%20x_1%7D)
Plug in two points from the line. Use the points (-4, -4) and (0, 3):
![m = \frac{-3 - (-4)}{0 - (-4)}](https://tex.z-dn.net/?f=m%20%20%3D%20%5Cfrac%7B-3%20-%20%28-4%29%7D%7B0%20-%20%28-4%29%7D)
Simplify:
m = 1/4.
Slope-intercept form is y = mx + b.
Find the 'b' value by finding the y-value at which the graph intersects the y-axis. This is at y = -3. Therefore, the equation is:
y = 1/4x - 3.
Answer:
The possible measures of the midsegment are <u>32 units and 212 units</u>.
Step-by-step explanation:
Given:
A triangle PQR with the midsegment made by sides PQ and PR has length equal to
and the base length QR opposite to the midsegment is
.
From midsegment theorem, we know that, the midsegment is a line parallel to the base opposite to it and half the length of the base length.
Therefore, Midsegment =
Base length QR
![8x^2+12x+36=\frac{1}{2}(4x^2+60x+120)\\\\8x^2+12x+36=2x^2+30x+60\\\\(8x^2-2x^2)+(12x-30x)+(36-60)=0\\\\6x^2-18x-24=0\\\\6(x^2-3x-4)=0\\\\x^2-3x-4=0\\\\x^2+x-4x-4=0\\\\x(x+1)-4(x+1)=0\\\\(x+1)(x-4)=0\\\\x=-1\ or\ x=4](https://tex.z-dn.net/?f=8x%5E2%2B12x%2B36%3D%5Cfrac%7B1%7D%7B2%7D%284x%5E2%2B60x%2B120%29%5C%5C%5C%5C8x%5E2%2B12x%2B36%3D2x%5E2%2B30x%2B60%5C%5C%5C%5C%288x%5E2-2x%5E2%29%2B%2812x-30x%29%2B%2836-60%29%3D0%5C%5C%5C%5C6x%5E2-18x-24%3D0%5C%5C%5C%5C6%28x%5E2-3x-4%29%3D0%5C%5C%5C%5Cx%5E2-3x-4%3D0%5C%5C%5C%5Cx%5E2%2Bx-4x-4%3D0%5C%5C%5C%5Cx%28x%2B1%29-4%28x%2B1%29%3D0%5C%5C%5C%5C%28x%2B1%29%28x-4%29%3D0%5C%5C%5C%5Cx%3D-1%5C%20or%5C%20x%3D4)
Now, midsegment can be calculated using the values of 'x'.
First, plug in -1 for 'x'. This gives,
![Midsegment=8(-1)^2+12(-1)+36\\\\Midsegment=8\times 1-12+36\\\\Midsegment=8-12+36=32\ units](https://tex.z-dn.net/?f=Midsegment%3D8%28-1%29%5E2%2B12%28-1%29%2B36%5C%5C%5C%5CMidsegment%3D8%5Ctimes%201-12%2B36%5C%5C%5C%5CMidsegment%3D8-12%2B36%3D32%5C%20units)
Now, plug in 4 for 'x'. This gives,
![Midsegment=8(4)^2+12(4)+36\\\\Midsegment=8\times 16-48+36\\\\Midsegment=128+48+36=212\ units](https://tex.z-dn.net/?f=Midsegment%3D8%284%29%5E2%2B12%284%29%2B36%5C%5C%5C%5CMidsegment%3D8%5Ctimes%2016-48%2B36%5C%5C%5C%5CMidsegment%3D128%2B48%2B36%3D212%5C%20units)
Therefore, the possible measures of the midsegment are 32 units and 212 units
If I did my math right the answer would be X = -5/4
hope this helps!