B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
Answer:
uh 14
Step-by-step explanation:
i did really just add 12+2
hope it help :)
Answer:
d=13988 or d=1.3988 x 10^4
Step-by-step explanation:
d=(-8)^2+(-118)^2
d=64+13924
d=13988
Answer:
d
Step-by-step explanation:
because both the measurement and the congruent side are opposite in sentence
X = k/p^3
125 = k/10^3 = k/1000
1000 x 125 = k
k = 125000
x = 125000/p^3
The profit is given by G = px - (125 + 2x) = p(125000/p^3) - 125 - 2(125000/p^3) = 125000/p^2 - 250000/p^3 - 125
For maximum profit:
dG/dp = 0
dG/dp = -250000/p^3 + 750000/p^4 = 0
750000 - 250000p = 0
p = 750000/250000 = 3
Therefore the price that will yeaild maximum profit is $3.
