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Basile [38]
2 years ago
7

I need help on this please!! Anyone

Mathematics
1 answer:
kow [346]2 years ago
6 0
What topic is this? And when is it due?
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What is the answer?
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3 years ago
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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do
expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) =3x^2 -2x +1

The two basic hypothesis of the mean valued theorem are

  • The function should be continuous in [0,2]
  • The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

   

4 0
3 years ago
What is the intersection of the three sets: A = {0, 2, 3, 6, 8}, B = {2, 3, 6, 8, 9}, and C = {1, 2, 4, 8, 9}? A. {2, 8, 9} B. {
Ugo [173]

Answer:

{2,8}

Step-by-step explanation:

This is the same thing as asking what element (in this case what number) is in all 3 sets.

0 isn't in all 3 sets because it isn't in B.

2 is in all 3 sets

3 isn't because it isn't in C

4 isn't in A.

6 isn't in C.

8 is in all 3 sets.

9 isn't in A

So the elements that are in the 3 sets are {2,8}.

8 0
3 years ago
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K-17=-12 I need help solveing this
Fed [463]
Remember, you can do ANYTHING to an equaiton as long as you do it to BOTH SIDES

we can try to get k by itself bymaking that -17 into 0 since k+0=k

-17+17=0 right so

K-17=-12
add 17 to BOTH SIDES
K+17-17=17-12
K+0=5
K=5
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Complete the proof.<br> Prove: AUWX - AUW<br> A)<br> AAS<br> B)<br> ASA<br> C)HL<br> D)<br> SAS
balu736 [363]

Answer:D) SAS

Step-by-step explanation:

USA test prep

8 0
3 years ago
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