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2 years ago

I need help on this please!! Anyone

Mathematics

1 answer:

kow [346]2 years ago

6 0

What topic is this? And when is it due?

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-10y + 18 = -3 (5y - 7) + 5y

Alecsey [184]

Answer:

-10y + 18 = -3 (5y - 7) + 5y

-10y + 18 = -18y + 21 + 5y

-10y + 18 = -13y + 21

Step-by-step explanation:

-10y + 18 = -3 (5y - 7) + 5y

-10y + 18 = -18y + 21 + 5y

-10y + 18 = -13y + 21

3 0

2 years ago

38<br> Is that a perfect square

fomenos

No cuz u have to be able to divide by 4 i think

7 0

2 years ago

Read 2 more answers

Rick knows that 1 cup of glue weighs 1/18 pound. He has 2/3 pound of glue. How many cups of glue does he have?

Basile [38]

$\begin{array}{ccc}1\ cup&-&\frac{1}{18}\ lb\ (pound)\\\\x\ cup&-&\frac{2}{3}\ lb\ (pounds)\end{array}\ \ \ \ \ \ cross\ multiply\\\\\\\frac{1}{18}x=1\times\frac{2}{3}\\\\\frac{1}{18}x=\frac{2}{3}\ \ \ \ \ \ |multiply\ both\ sides\ by\ 18\\\\18\times\frac{1}{18}x=18\times\frac{2}{3}\\\\x=6\times2\\\\\boxed{x=12}\\\\Answer:He\ has\ 12\ cups\ of\ glue.$

6 0

3 years ago

David has $100.00 saved in the bank. a payment is taken out of his account for $150.00. he makes a deposit for $50.00 but at the

Dmitry_Shevchenko [17]

Gimme a few mins, imma edit this later... ;-;

6 0

3 years ago

Read 2 more answers

A village wishes to measure the quantity of water that is piped to a factory during a typical morning. A gauge on the water line

anzhelika [568]

Answer:

570 m³

Step-by-step explanation:

The volume of water is the product of flow rate of water and the time taken. We are to get the volume of water used between 6 am and 9 am, that is for 3 hours (9 - 6).

We are given the flow rate at 6 am and the flow rate at 9 am, but this flow rate changes between 6 am and 9 am. To get the estimate of the water used, Let us assume that it flows at the same flow rate as it was at 6 am throughout, hence:

$V_L= 100 m^3/h * 3h=300\ m^3$

Also, let us assume that it flows at the same flow rate as it was at 9 am throughout, hence:

$V_R= 280 m^3/h * 3h=840\ m^3$

To get the best estimate of the total volume, let us find the average of the two values, hence:

$Volume=\frac{V_L+V_R}{2} =\frac{300+840}{2}=570\ m^3$

3 0

2 years ago