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Basile [38]
2 years ago
7

I need help on this please!! Anyone

Mathematics
1 answer:
kow [346]2 years ago
6 0
What topic is this? And when is it due?
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Simplify 7(2x+y)+6(×+5y)
iris [78.8K]

Simplify, <em>7(2x+y)+6(x+5y).</em>

<em>a:</em> <em>20x+37y</em>

<em> (7 • (2x + y)) +  6 • (x + 5y) </em>

<em>Step  2  : </em>

<em>Equation at the end of step  2  : </em>

<em>  7 • (2x + y) +  6 • (x + 5y) </em>

<em>Step  3  : </em>

<em>Final result : </em>

<h3><em> </em><em> 20x + 37y</em></h3>

Thanks,

<em>Deku ❤</em>

4 0
3 years ago
Teams of four are competing in a quarter-mile relay race. Each runner must run the same excavation distance. What is the distanc
densk [106]
Each teammate would run 330 feet because a quarter mile is 1320 feet and 1320/4=330
7 0
3 years ago
Find the value of x that makes the lines parallel
Andreyy89
The equation is
8x +7=125
8 0
3 years ago
Read 2 more answers
PLSSS HELP ME i need helppp
kozerog [31]
Answer: 12.56



Explanation: 4x3.14


3 0
2 years ago
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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