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Otrada [13]
1 year ago
6

How many faces, edges and vertices does the shape below have? Faces: Edges: Vertices:

Mathematics
1 answer:
olga55 [171]1 year ago
5 0

the number of faces, edges and vertices the shape below has is 4, 4 and 6 respectively.

<h3>How to determine the number</h3>

It is important to note that according to Euler’s formula for any convex polyhedron, the number of Faces (F) and vertices (V) added together is exactly two more than the number of edges (E).

It is mathematically written as;

Face + vertices = 2 + edges

F + V = 2 + E

From the figure given, we can see that it is a kite

Number of vertices = 4

Number of faces = 4

2 + edges = faces + vertices

2 + edges = 4 + 4

2 + edges = 8

Edges = 8 - 2

Edges = 6

Thus, the number of faces, edges and vertices the shape below has is 4, 4 and 6 respectively.

Learn more about a kite here:

brainly.com/question/20597161

#SPJ1

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The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

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Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

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<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

Now equate the x-coordinate.

$ \frac{m+h}{2}=\frac{x}{2}

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x = m + h

Now equate the y-coordinate.

$\frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

n = y

y = n

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