What is the slope of the line passing through the points (0, 4) and (-8, -1)?

Mathematics

1 answer:

Bas_tet [7]2 years ago

7 0

Answer:

0.625

Step-by-step explanation:

Given the points :

(0, 4) and (-8, -1)

x1 = 0 ; y1 = 4

x2 = - 8 ; y2 = - 1

Slope, m = rise / run

Rise = y2 - y1 = - 1 - 4 = - 5

Rise = x2 - x1 = - 8 - 0 = - 8

The slope, m = - 5 / - 8

Slope, m = 0.625

You might be interested in

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$