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3 years ago

What is the slope of the line passing through the points (0, 4) and (-8, -1)?

Mathematics

1 answer:

Bas_tet [7]3 years ago

7 0

Answer:

0.625

Step-by-step explanation:

Given the points :

(0, 4) and (-8, -1)

x1 = 0 ; y1 = 4

x2 = - 8 ; y2 = - 1

Slope, m = rise / run

Rise = y2 - y1 = - 1 - 4 = - 5

Rise = x2 - x1 = - 8 - 0 = - 8

The slope, m = - 5 / - 8

Slope, m = 0.625

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A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

A function follows the rule y = -75 - 5 x . When the function's output is 25, the equation is 25 = -75 - 5 x .

zhenek [66]

Answer:

same here idek tbh

Step-by-step explanation:

.......

3 0

3 years ago

Help with this question please ASAP!! :)

Ivan

Answer:

options 1, 3, and 6.

Step-by-step explanation:

on the diagram, ∠2 is in the area of line EA and EG. If you are reading it by letters, ∠GEA is equal to ∠2 because they are in the same area. The last option (6) being ∠AEG, the middle angle is E which is the same as ∠GEA and ∠2.

hope this helps!! :))

6 0

3 years ago

Read 2 more answers

(Segment Proofs)

Anni [7]

Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

Thus, by substitution, we can deduce that; KL = LM

Thus is because JK can be replaced with KL and MN can be replaced with LM.

Thus, it is proved that KL = LM

4 0

3 years ago

Mark said, "in the data set,4, 5, 5, 8, the mean and mode the same. " Is he correct? Explain why or why not in your explanation

Vinvika [58]

Answer:

Step-by-step explanation:

the mean is 16 (add 4+5+5+8, then divide answer by 4) and the mode is 5 (occurs most in data)

5 0

2 years ago