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3 years ago

What is the slope of the line passing through the points (0, 4) and (-8, -1)?

Mathematics

1 answer:

Bas_tet [7]3 years ago

7 0

Answer:

0.625

Step-by-step explanation:

Given the points :

(0, 4) and (-8, -1)

x1 = 0 ; y1 = 4

x2 = - 8 ; y2 = - 1

Slope, m = rise / run

Rise = y2 - y1 = - 1 - 4 = - 5

Rise = x2 - x1 = - 8 - 0 = - 8

The slope, m = - 5 / - 8

Slope, m = 0.625

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23 tens is the same as

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2 years ago

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-27=-3p+15-3p solve the equation and show your work

Gnesinka [82]

-27 = -3p + 15 - 3p

Combine like terms.
-3p -3p = (-3-3)p = -6p

-27 = -6p + 15

Subtract 15 from each side to get the variable term on its own.

-27 - 15 = -6p + 15 - 15

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Divide each side by -6 to find p.

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3 years ago

A competitive diver dives from a 33-foot high diving board. The height of the diver in feet after 't' seconds is given by u(t) =

ludmilkaskok [199]

Answer:

$t = 0.375s$

Step-by-step explanation:

Given

$h(t) = -16t^2 + 4t + 33$ --- driver 1

$Rate = 2ft/s$ -- driver 2

$height = 33ft$

Required

The time they passed each other

First, we determine the function of driver 2.

We have that:

$Rate = 2ft/s$ and $height = 33ft$

So, the function is:

$h_2(t) = Height - Rate * t$

$h_2(t) = 33 - 2t$

The time they drive pass each other is calculated as:

$h(t) = h_2(t)$

$-16t^2 + 4t + 33= 33 - 2t$

Collect like terms

$-16t^2 + 4t + 2t= 33 - 33$

$-16t^2 + 6t= 0$

Divide through by 2t

$-8t + 3= 0$

Solve for -8t

$-8t = -3$

Solve for t

$t = \frac{-3}{-8}$

$t = 0.375s$

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2 years ago

What's the answer?????????

PSYCHO15rus [73]

Omg! fellow k12 student:)

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2 years ago

A line passes through the point (9. -9) and has a slope of -4/3.

professor190 [17]

Answer:

$y = \frac{ - 4}{3} x + 3$

Step-by-step explanation:

$using \: point \: slope \: form \\ y - y1 = m(x - x1) \\ y + 9= \frac{ - 4}{3} (x - 9) \\ y + 9= \frac{ - 4}{3}x + 12\\ y = \frac{ - 4}{3} x + 3$

6 0

2 years ago