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2 years ago

Please help I don’t get the questions

Mathematics

1 answer:

katovenus [111]2 years ago

7 0

Choose 2 points and then the x will be like 3 and the y -3 and the equation y = 3x-3

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7/10 divided by -2/7

Tpy6a [65]

Answer:

1/20

Step-by-step explanation:

hope this helps

6 0

1 year ago

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For lunch you can pick a main item (pizza or sandwich), a side item (fruit, veggie or chips) and a drink (milk or juice). How ma

lidiya [134]

Answer:

6

Step-by-step explanation:

There are 2 options for 3 items.

So multiple 2 by 3, and you can have a range of 6 lunches able to be chosen.

2 x 3 = 6

4 0

3 years ago

PLEASE HELP AHHHH IS URGENT.

telo118 [61]

Answer:

z=96, because we know that any straight line is equivalent to 180 degrees, so we subtract 180-48-36=96.

To find x we first make an equation 6x+96+36=180
6x+132=180
6x=180-132
6x=48
6x/6=48/6
x=8

and also cause why not y=96 as well same principle applies.

7 0

3 years ago

Find the derivative of f(x)= (e^ax)*(cos(bx)) using chain rule

Vikentia [17]

$f(x) = e^{ax}\cos(bx)$

then by the product rule,

$f'(x) = \left(e^{ax}\right)' \cos(bx) + e^{ax}\left(\cos(bx)\right)'$

and by the chain rule,

$f'(x) = e^{ax}(ax)'\cos(bx) - e^{ax}\sin(bx)(bx)'$

which leaves us with

$f'(x) = \boxed{ae^{ax}\cos(bx) - be^{ax}\sin(bx)}$

Alternatively, if you exclusively want to use the chain rule, you can carry out logarithmic differentiation:

$\ln(f(x)) = \ln(e^{ax}\cos(bx)} = \ln(e^{ax})+\ln(\cos(bx)) = ax + \ln(\cos(bx))$

By the chain rule, differentiating both sides with respect to x gives

$\dfrac{f'(x)}{f(x)} = a + \dfrac{(\cos(bx))'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a - \dfrac{\sin(bx)(bx)'}{\cos(bx)} \\\\ \dfrac{f'(x)}{f(x)} = a-b\tan(bx)$

Solve for f'(x) yields

$f'(x) = e^{ax}\cos(bx) \left(a-b\tan(bx)\right) \\\\ f'(x) = e^{ax}\left(a\cos(bx)-b\sin(bx))$

just as before.

4 0

2 years ago

4. Ms. Hwang started reading at 3:35 p.m. She finished reading at 4:16 p.m.

Montano1993 [528]

She read for 41 minutes

7 0

2 years ago

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