Answer:a government website/A.Gov
Explanation:
I looked it up I also put this as my answer so i don’t know if it’s right or not
Answer:
R = 1 kΩ
i_L = 2.2 mA
Explanation:
The complete question is given in attachment:
Given:
- The gain i_L / i_i = 11
- Given circuit Attachment
Find:
- Find the required value of R
- If the amplifier is fed with a current source having a current of 0.2 mA and a source resistance of 10 kΩ, find iL
Solution:
- Use KVL on right most loop (load loop):
v_x = 0 - i_i*10 = -10i_i
- Using ohm's law:
i = (0 - v_x) / R
i = 10*i_i / R
- Use KCL at the node:
i_L = i + i_i
- Substitute the the two i:
i_L = 10*i_i / R + i_i
i_L / i_i = ( 10/ R + 1 )
11 = ( 10/ R + 1 )
10 / R = 10
R = 1 kΩ
- The input resistance = 0 because there is a virtual ground at input. Then the value of source resistance will have no effect on resulting i_l, hence:
i_L = i_L / i_i * i_i
i_L = 11*0.2
i_L = 2.2 mA
Answer:
a. Heat Capacity = 1.756J/mol-K
b. Heat Capacity = 24.942J/mol-k
Explanation:
Given
Constant volume Cv = 0.81J/mol-k
T1 = 34K
Td = Debye temperature = 306 K. Estimate the heat capacity (in J/mol-K) a. 44 K
First, The value of the temperature-independent constant.
Using Cv = AT³
Make A the subject of formula
A = Cv/T³
Substitute each values
A = 0.81/34³
A = 0.000020608589456543
A = 2.061 * 10^-5J/mol-k
The heat capacity changes with the temperature; below is the relationship between heat capacity and the temperature
Cv = AT³
So, The heat capacity when T = 44k is then calculated as
Cv = 2.061 * 10^-5 * 44³
Cv = 1.755522084266232
Cv = 1.756J/mol-K
(b) at 477 K.
Because the temperature is larger than the Debye temperature, the specific heat is calculated using as:
Cv = 3R
Where R = universal gas constant
R = 8.314J/mol-k
Cv = 3 * 8.314
Cv = 24.942J/mol-k
Answer:In fact, engineers have completely changed the world we live in, from modern homes, bridges, space travel, cars and the latest mobile technology. Innovative ideas are at the heart of what engineers do, and they use their knowledge to create new and exciting prospects and solve any problems that may arise.
Explanation:
yea:D
Answer:
Explanation: Peak – the highest point above the rest position. Trough – the lowest point below the rest position. Amplitude – the maximum displacement of a point of a wave from its rest position. Wavelength – distance covered by a full cycle of the wave. Usually measured from peak to peak, or trough to trough.
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