Question

A bridge foundation has a nominal load capacity of 1700kN. If the resistance factor for this foundation is 0.65, what is the ultimate factored load this foundation can carry using the LRFD method

Answer 1

Answer:

The appropriate answer will be "2353.8 K". A further solution is given below.

Explanation:

The given values are:

Ultimate capacity,

= 1700kN

Resistance factor,

F.S = 0.65

According to the the LRFD, the allowable bearing pressure will be:

⇒ $Pallo w = \phi_c\times \frac{Pn}{F.S}$

On substituting the values, we get

⇒             $=0.9\times \frac{1700}{0.65}$

⇒             $=2353.8 \ K$

According to the the ASD, the allowable bearing pressure will be:

⇒ $Pallow=\frac{Pn}{\Omega \times F.S}$

On substituting the values, we get

⇒             $=\frac{1700}{1.67\times 0.65}$

⇒             $= \frac{1700}{1.0855}$

⇒             $=1845.35 \ K$