3 years ago

prove that the heat transfer at the constant pressure is given by the enthalpy change during the process

1 answer:

mihalych1998 [28]3 years ago

5 0

Answer:

at constant pressure, the heat flow for any process is equal to the change in the internal energy of the system plus the PV work done. Comparing the previous two equations shows that at constant pressure, the change in the enthalpy of a system is equal to the heat flow: ΔH=qp.

Explanation:

Give brainliest

You might be interested in

Can i use two shunts and one meter

Lyrx [107]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

As Becky was driving "Old Betsy," the family station wagon, the engine finally quit, being worn out after 171,000 miles. It can

andriy [413]

Answer:

1) 4.361 x 10 raised to power 8 revolutions

2) 1.744 x 10 raised to power 9 firings

3) 2.18 x 10 raised to power 8 intake strokes

Explanation:

The step by step explanation is as shown in the attachment

8 0

3 years ago

A segment of four-lane freeway (two lanes in each direction) has a 3% upgrade that is 1500 ft long followed by a 1000-ft 4% upgr

Dennis_Churaev [7]

Answer:

The level of service of of compound grade freeway is LOSB.

Explanation:

Find the provided attachments for explanation

3 0

3 years ago

What happens when the arms of the milky move away from the center of the galaxy

Alina [70]

Well this question is though because we have never seen such a thing ! and to be quite frank when that happens , nothing good comes from it. Black Holes

6 0

3 years ago

A missile flying at high speed has a stagnation pressure and temperature of 5 atm and 598.59 °R respectively. What is the densit

alexdok [17]

Answer:

$5.31\frac{kg}{m^3}$

Explanation:

Approximately, we can use the ideal gas law, below we see how we can deduce the density from general gas equation. To do this, remember that the number of moles n is equal to $\frac{m}{M}$ , where m is the mass and M the molar mass of the gas, and the density is $\frac{m}{V}$ .

For air $M=28.66*10^{-3}\frac{kg}{mol}$ and $\frac{5}{9}R=K$

So, $598.59 R*\frac{5}{9}=332.55K$

$pV=nRT\\pV=\frac{m}{M}RT\\\frac{m}{V}=\frac{pM}{RT}\\\rho=\frac{pM}{RT}\\\rho=\frac{(5atm)28.66*10^{-3}\frac{kg}{mol}}{(8.20*10^{-5}\frac{m^3*atm}{K*mol})332.55K}=5.31\frac{kg}{m^3}$

7 0

3 years ago

prove that the heat transfer at the constant pressure is given by the enthalpy change during the process​

prove that the heat transfer at the constant pressure is given by the enthalpy change during the process