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Readme [11.4K]
4 years ago
11

Start with x2 + 4x = 12 and complete the square, what is the equivalent equation? A) (x + 2)2 = 16 B) (x + 2)2 = 14 C) (x + 4)2

= 16 D) (x + 4)2 = 28
Mathematics
1 answer:
alexira [117]4 years ago
8 0

Answer: The answer is A

Step-by-step explanation: Add the coefficient of x to the both sides.

X²+4x=12

X²+4x+4=12+4

X²+4x+4=16

X²+2x+2x+4=16

X(x+2)+2(x+2)=16

(X+2)(x+2)=16

(X+2)²=16

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Simplify 6*3+4+2*3(15)+*2
Angelina_Jolie [31]

Answer:

114.

Step-by-step explanation:

  1. remove parenthesis
  2. multiply the numbers 6 x 3 + 18

18 + 4 + 2 x 3 x 15 + 2

multiply the numbers 2 x 3 x 15 + 90

18 + 4 + 2 + 90 + 2

add the numbers : 18 + 4 + 2 + 90 + 2

= 114!

5 0
3 years ago
A juice stand sells smoothies in cone-shaped cups that are 8 in. tall. The regular size has a 4 in. diameter. The jumbo size has
nirvana33 [79]
All cone-shaped cups have the same height in 8 inches. They just differ in their diameters. To solve for the volume of the regular and jumbo sizes, let's use the formula for the volume of cone

V = (1/3)*pi*(r^2)*h

r is just the half of the diameter, h is the height which is equal to 8

Regular size:
V = (1/3)*pi*((4/2)^2)*8
V = 33.5 cube inches

Jumbo size:
V = (1/3)*pi*((8/2)^2)*8
V = 134.0 cube inches
3 0
3 years ago
Solve the system by elimination 4x-y=2 and x+3y=7
alexdok [17]

Answer:

x=1 y=2

Step-by-step explanation:

Isolate x for 4x -y=2: X=2+y/4

Substitute x= 2+y/4

(2+y/4 )+3y=7

simplify 2+13y/4=7

Isolate y for 2+13y/4=7

y=2

Forx= 2+y/4

Substitute y = 2

x= 2+2/4

Simplify

X=1

3 0
2 years ago
URGENT! PLEASE HELP.
Harrizon [31]

The distance BC from Tower 2 to the plane will be 14,065.5 ft and the height of the plane from the ground will be 5,720.9 ft.

<h3>What is a right-angle triangle?</h3>

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

A plane is located at C on the diagram.

There are two towers located at A and B.

The distance between the towers is 7600 feet and angles of elevation are given.

Then in the right-angle triangle ΔADC, we have

\rm \tan 16 = \dfrac{H}{7600 + X}\\\\\\H = 0.2867(7600 +X)\\\\\\H = 0.2756\ X + 2179.2649 ...1

Then in the right-angle triangle ΔBDC, we have

\rm \tan24 = \dfrac{H}{ X}\\\\\\H = 0.4452\ X ...2

From equations 1 and 2, we have

0.4452X = 0.2756 X + 2179.2649

0.1696X = 2179.2649

            X = 12849.439 ≅ 12,849.4 ft

Then the distance BC from Tower 2 to the plane will be

\rm BC = \dfrac{12849.4}{\cos 24}\\\\\\BC = 14065.5 \ ft

Then the height of the plane from the ground will be

\rm H = 12849.4 \times  \tan 24 \\\\\\H = 5720.9 \ ft

The figure is shown below.

More about the right-angle triangle link is given below.

brainly.com/question/3770177

#SPJ1

3 0
2 years ago
The coordinates of which point are (–3, –6)? On a coordinate plane, point A is (negative 3, 6), point B is (negative 6, negative
julia-pushkina [17]

Answer:

Point c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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