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Naya [18.7K]
3 years ago
9

5/9 , 4/15 ,dan 3/5

Mathematics
1 answer:
vichka [17]3 years ago
5 0
4/15, 5/9 and 3/5.

Hope this helps! :)
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P(A) = 0.14. P(B) = 0.24, and P(A and B) = 0.19. Find P(A given B). Round your
Ket [755]

Answer: The required probability is 0.79

Step-by-step explanation:

Given: P(A) = 0.14

P(B) = 0.24

P(A and B) = 0.19

To find:  P(A given B)

The conditional probability of an event A is the probability that the event will occur given the knowledge of an already occurred event B and is denoted by

P(A/B) or P(A \text { given } B) where the value of P(A/B)= \dfrac{P(A \text { and } B)}{P(B)}

So we have

P(A/B) = \dfrac{0.19}{0.24} \approx 0.79

Hence ,the required probability is 0.79

3 0
3 years ago
A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the we
zepelin [54]
<h2>Answer with explanation:</h2>

Given : A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the weight control measurement is (in grams) are :

X= 155.1, 154.8, 155.5, 155.3, and 154.6.

here, n=5

The average weight :\overline{x}=\dfrac{\sum^{i=5}_{i=1}x_i}{n}

=\dfrac{155.1+154.8+155.5+155.3+154.6}{5}\\\\=\dfrac{775.3}{5}=155.06

∴ Average weight (\overline{x})=155.06 grams

Uncertainty = Standard deviation: \sigma=\sqrt{\dfrac{\sum^{i=5}_{i=1}(x_i-\overline{x})^2}{n}}

=\sqrt{\dfrac{(0.04)^2+(-0.26)^2+(0.44)^2+(0.24)^2+(-0.46)^2}{5}}

=\sqrt{\dfrac{0.532}{5}}=\sqrt{0.1064}=0.326190128606\approx0.33

i.e. Its uncertainty : \sigma=0.33

The fractional uncertainty = \dfrac{\sigma}{\overline{x}}

=\dfrac{0.33}{155.06}=0.00212820843544\approx0.002

7 0
4 years ago
Whats 851,708 to the nearest hundred-thousand
inn [45]

Answer:

900,000

Step-by-step explanation:

because when you round  number from 1-4 you put it down example: 1223

round to nearest thousand it is 1000 but when 5-9 is higher example: 1566 it is 2000

4 0
3 years ago
Read 2 more answers
The Denver Post reported that, on average, a large shopping center had an incident of shoplifting caught by security 2.3 times e
bezimeni [28]

Answer:

9 hours

Step-by-step explanation:

6 0
3 years ago
Which reason justifies step 2 in the proof, if it all the pictures are in this question I’ll make another question.
IRISSAK [1]
Could you have a bit more clarification so there shall be a better understanding toreares your questions
8 0
4 years ago
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