Question

Helppp? I don’t understand trigonometry at all

Answer 1

Answer:

Step-by-step explanation:

Actually, the answer is the second graph from the left. In

$y=3sin\frac{1}{3}x$ , the 1/3 represents the "b" value in the equation for the period (length of one revolution) of the function. The period is found in

$\frac{2\pi}{b}$ and since our b value is 1/3:

$\frac{2\pi}{\frac{1}{3} }=\frac{2\pi}{1}*\frac{3}{1}=6\pi$

That means that one revolution is 6pi units long. The amplitude (the number out in front of the sin) is how high it goes up and down from the midline (the x-axis). The third graph from the left shows a function with a period of 2pi, which is the normal period for a sin function.

Answer 2

Answer:

The diagram presented on Third expresses the graph of

$y = 3 \sin( \frac{1}{3}x )$

Hope it helps!