Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:
work is shown and pictured
I think the first one is correct. Since “three less than z squared” insinuate that the value is 3 units less than the value z^2
Answer:
The correct answer is 8cm.
Step-by-step explanation:
Vol. Of cone= 1/3pi r²h
= 1/3×3.14× 8²×15
= 8×8×5×3.14
64× 5×3.14
= 320×314/100
=16×314=5024 cm³
Hope this helps:) Goodluck!
Answer: there is no N in the equation
Step-by-step explanation:
