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Brilliant_brown [7]
1 year ago
3

Which radical expression is equivalent to

Mathematics
1 answer:
lyudmila [28]1 year ago
3 0

~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] ~\dotfill\\\\ a^{\frac{1}{5}}\implies \sqrt[5]{a^1}\implies \sqrt[5]{a}

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Answer:  The correct answer is:

______________

            →   Choice: [C]:  "  \frac{2}{1} * \frac{7}{-2} " .

______________

Step-by-step explanation:

______________

Note that this problem contains multiplication and division.

 WIth multiplication and division;

the order of operations we perform is from "left side to right side" in the expression;  in the order in which the operation occurs:

As such:

______________

The given problem:

______________

"   \frac{-3}{4} * \frac{7}{-2} ÷ \frac{3}{-8} " ;

Is treated as:

______________

" (\frac{-3}{4} * \frac{7}{-2}) ÷ \frac{3}{-8} " ;

______________

So, we start with:

______________

" \frac{-3}{4} * \frac{7}{-2} " ;

______________

→ \frac{-3}{4} * \frac{7}{-2} = \frac{(-3*7)}{[4*(-2) ]} = \frac{-21}{-8} ;  

______________

Simplify:

______________

"  \frac{-21}{-8} = \frac{(-1)*21}{(-1) *8} " ;

______________

          →  The "(-1)'s " cancel out:

              {since: "(-1)/(-1) = 1 "} ;

→ And we have:  " \frac{21}{8} " ;

______________

Now, continue with the problem, and divide this value by: " \frac{3}{-8} " ;

______________

 " \frac{21}{8} ÷ \frac{3}{-8} " ;

______________

Note that dividing by a number is the same as multiplying by the reciprocal of that said number:

______________

The reciprocal of " \frac{3}{-8} " ; is:  " \frac{-8}{3} : l

As such:

" \frac{21}{8} ÷ \frac{3}{-8} " ;

______________

     =   "  \frac{21}{8} * \frac{-8}{3}  "

______________

Now, let us simplify:

 Note:  The "8" and the "-8" ;

    The "8" can be changed to "1" ; and the "-8" can be changed to "-1" ;

since: "-8 ÷ 8 = 1 " ;  and since:  "8 ÷ 8 = 1 " ;

Note:  The "3" and the "21" ;

    The "3" can be changed to "1";  and the "21" can be changed to "7" ;

since: "21 ÷ 3 = 7 " ; and since:  "3 ÷ 3 = 1 " ;

______________

And we can we rewrite the expression:

______________

 → " \frac{7}{1} * \frac{-1}{1} " ;

which equals:  " 7 * -1 " ;  which equals " - 7 ".

______________

Now, the problem has 4 (four) answer choices.  Which expression [i.e. which answer choice] is equal to:  " -7 " ??

______________

Consider Choice [A]: " \frac{1}{2} * \frac{7}{2} " ; which equals: " \frac{(1*7)}{(2*2)} = \frac{7}{4} = 1\frac{3}{4} " ;

" 1\frac{3}{4} \neq -7 ."

Rule out: "Choice [A]."

______________

Consider Choice: [B]: " \frac{2}{1} * \frac{7}{2} " ; which equals: " \frac{(2*7)}{(1*2)} = \frac{14}{2} = 7 ; " 7\neq -7 ."

Rule out: "Choice: [B]."

______________

Consider Choice: [C]: " \frac{2}{1} * \frac{7}{-2} " ; which equals: " -7 ;  " -7 = -7 ".  

 Choice [C]: seems correct!

______________

Consider Choice: [D]: " \frac{-1}{2} * \frac{7}{-2} " ; which equals:

                           " \frac{(-1*7)}{(2*-2)} = \frac{-7}{-4} = \frac{(-1)*7}{(-1)*4} ;

                                              → cancel out the "(-1)'s" ;

                                              → {since: "(-1) / (-1) = 1 " ;  

                                         to get:

                                              → " \frac{7}{4} " ; which equals:

                                              → " 1\frac{3}{4} " ;  " 1\frac{3}{4} \neq -7 . "

 Rule out: "Choice: [D]."

______________

The correct answer is:

______________

Choice: [C]:  "  \frac{2}{1} * \frac{7}{-2} " .

______________

Hope this is helpful to you!

Wishing you the best!

______________

4 0
3 years ago
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