Is there an ordered pair that is a solution to both 4x+3y<12 and -x+3y<-3
1 answer:
Answer:
See below.
Step-by-step explanation:
4x + 3y < 12
-x + 3y < -3
First find where the 2 lines intersect
4x + 3y = 12
-x + 3y = -3
Subtract :
5x = 15
x = 3
and y = -3 + 3 / 3 = 0
So they intersect at the point (3,0).
Therefore there are many ordered pairs below these 2 lines that satisfy this inequality.
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