The average of 7 numbers is 45.If the last two numbers are 27 and 43 what is the average of the first five

Mathematics

1 answer:

Paul [167]3 years ago

4 0

Answer:

Step-by-step explanation:

The average is calculated as

average = $\frac{sum}{count}$ Given the average of 7 numbers is 45 , then

$\frac{sum}{7}$ = 45 ( multiply both sides by 7 )

sum of 7 numbers = 315

Subtract 27, 43 from the sum to obtain the sum of first 5 numbers

315 - (27 + 43) = 315 - 70 = 245 , then

average of first 5 numbers = $\frac{245}{5}$ = 49

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