Answer:
A) 17 m B) 20.8 m
Step-by-step explanation:
I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11
26-11 = 15
I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)
AB is the hypotenuse
We can use the pythagorean theorem to find length AB (a^2 + b^2 = c^2)
a and b is the legs which is 8 and 15
8^2 + 15^2 = AB^2
64 + 225 = AB^2
289 = AB^2
√289 = AB (to undo a square, you use square roots)
√289 = 17
AB = 17 m
Now we need to find the hypotenuse of AC
the same thing, we did for problem A, use the pythagorean theorem
17^2 + 12^2 = AC^2
289 + 144 = AC^2
433 = AC^2
√433 = AC
√433 is <em>about </em>20.808...
round to the tenth as stated in the directions
AC = 20.8 m
3*10 = 10+5*s
30 = 10+5s
20 = 5s
s = 4
Answer:
Step-by-step explanation:
Answer:
23/12 or 1 and 11/12
Step-by-step explanation:
Your first step is that you need to gain a common denomitor. In this scenario, this is 12. To get this, you can either go through the given factors such as 3 having the factors of 6, 9, and 12 and 4 having the factors of 8, and 12.
Another method is the multiply the two given denominators together, but there are certain instances where you shouldn't do that.
Now that you have a common denominator, you need to change the numerators to accomadate the denominators. For 3 to turn into 12, you need to multiply it by 4, thus you have to do the same to the numerator. For 4 to turn into 12, you need to multiply it by 3. This will give you these two new fractions:
8/12 + 15/12
Add the numerators to get 23/12 and then simplify the two numbers to get the mixed number of 1 and 11/12.
Hope this helps!
