The average of 7 numbers is 45.If the last two numbers are 27 and 43 what is the average of the first five
1 answer:
Answer:
49
Step-by-step explanation:
The average is calculated as
average = Given the average of 7 numbers is 45 , then
= 45 ( multiply both sides by 7 )
sum of 7 numbers = 315
Subtract 27, 43 from the sum to obtain the sum of first 5 numbers
315 - (27 + 43) = 315 - 70 = 245 , then
average of first 5 numbers = = 49
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Answer:
We can be 95% certain that the sample mean will fall within $44.87 and $46.93
Step-by-step explanation:
Empirical Rule:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Central Limit Theorem:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Population:
Mean $45.90, standard deviation $10.31.
Sample:
By the Central limit theorem, mean $45.90, standard deviation
Which interval can the branch manager be 95% certain that the sample mean will fall within?
By the Empirical Rule, within 2 standard deviations of the mean. So
45.90 - 2*0.5155 = $44.87
45.90 + 2*0.5155 = $46.93
We can be 95% certain that the sample mean will fall within $44.87 and $46.93