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Karo-lina-s [1.5K]
2 years ago
7

In a study on the placebo effect on 100 students, 64 were found to perform better on tests after taking a fake pill to improve c

oncentration. What is the experimental probability the placebo pill induced better concentration on the student exams?
Mathematics
1 answer:
Zepler [3.9K]2 years ago
8 0

The experimental probability the placebo pill induced better concentration on the student exams is 0.64

The question has to do with probability.

<h3>What is probability?</h3>

Probability is the likelihood of an event occurring.

The probability of an event A is given by

P(A) = number of occurrences of event A/total number of occurrences of all events.

<h3>What is the experimental probability the placebo pill induced better concentration on the student exams?</h3>

Given that in the study on the placebo effect on 100 students, 64 were found to perform better on tests after taking a fake pill to improve concentration.

The event A = students performing better.

Since 64 students performed better, the number of occurrences of event A = 64.

Since there were 100 students, the total number of occurrences = 100.

So, P(A) = P(students perform better)

= number of occurrences of event A/total number of occurrences of all events.

= 64/100

= 0.64

So, the experimental probability the placebo pill induced better concentration on the student exams is 0.64

Learn more about probability here:

brainly.com/question/25839839

#SPJ1

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write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)
dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is y - 3 = \frac{-7x}{2}+ \frac{21}{4}

<h3><u>Solution:</u></h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

<em><u>The slope "m" of the line is given as:</u></em>

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here the given points are A(-2,2) and B(5,4)

\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4

m=\frac{4-2}{5-(-2)}=\frac{2}{7}

Thus the slope of line with given points is \frac{2}{7}

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}

The perpendicular bisector will run through the midpoint  of the given points

So let us find the midpoint of A(-2,2) and B(5,4)

<em><u>The midpoint formula for given two points is given as:</u></em>

\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Substituting the given points A(-2,2) and B(5,4)

m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x - x_1)

\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)

y - 3 = \frac{-7}{2}(x - \frac{3}{2})\\\\y - 3 = \frac{-7x}{2}+ \frac{21}{4}

Thus the equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is found out

7 0
4 years ago
(6a+11) <br><br>(2a + 83) <br><br>A) 21<br><br>B) 17<br><br>C) 18 <br><br>D) 20 <br><br>(20points)
Neporo4naja [7]
(6a+11)=(2a+83)
6a+11=2a+83
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6 0
3 years ago
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USPshnik [31]

Answer:

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Step-by-step explanation:

The computation of the next line in the sequence is shown below:

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i.e.

1 + 7 + 13 + 19 = 4 × 10

As 1 + 7 + 13 + 19 = 40

And 40 = 4 × 10

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7 0
3 years ago
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