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MaRussiya [10]
1 year ago
5

In mr. wilson's geometry class, 12 of the students received a's and 20 received b's. in his statistics class, 11 of the students

got a's and 15 got b's. in which class did mr. wilson's students earn a higher ratio of a's to b's? a. statistics b. neither, the ratios are equivalent c. geometry d. not enough information
Mathematics
1 answer:
Ainat [17]1 year ago
7 0

In (A) statistics class Wilson's students earn a higher ratio of a's to b's.

<h3>What are ratios?</h3>
  • A ratio in mathematics describes how many times one number contains another.
  • For example, if a dish of the fruit contains eight oranges and six lemons, the orange-to-lemon ratio is eight to six.
  • Similarly, the lemon to orange ratio is 6:8, while the orange to total fruit ratio is 8:14.

To find the higher ratio:

Given -

  • Geometry class = a:b = 12:20 = 3:5
  • Statistics class = a:b = 11:15

As we can observe that 3:5 < 11:15.

Therefore, in (A) statistics class Wilson's students earn a higher ratio of a's to b's.

Know more about ratios here:

brainly.com/question/2328454

#SPJ4

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3 years ago
Simplify the expression:<br> (2p + 1)(2) =
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Answer:

4p +2

Step-by-step explanation:

(2p + 1)(2)

Distribute

2p * 2 + 1*2

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3 years ago
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Find the 78th term of the arithmetic sequence –4,-2,0,...
MArishka [77]

The number is increasing by 2 every time.

78 x 2 = 156

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The 78th term is 152

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3 years ago
I need the answer for this problem please
Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

4 0
4 years ago
Using Triangle Similarity Theorems (6)
Fantom [35]

Answer:

DC = 3

Step-by-step explanation:

Based on triangle similarity theorem, we would have the following equation:

\frac{AD}{AC} = \frac{AE}{AB}

Plug in the values

\frac{9}{9 + DC} = \frac{12}{12 + 4}

\frac{9}{9 + DC} = \frac{12}{16}

\frac{9}{9 + DC} = \frac{3}{4}

Cross multiply

3(9 + DC) = 9×4

27 + 3DC = 36

Subtract 27 from each side

3DC = 36 - 27

3DC = 9

Divide both sides by 3

DC = 9/3

DC = 3

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3 years ago
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