1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Montano1993 [528]
3 years ago
9

Tom used 5/8 yards of ribbon to tie weights on the tail of his kite he cut the length of ribbon into equal pieces that were 1/12

yard long how many pieces each 1/12 yard long did Tom cut from the 5/8 ribbon
Mathematics
2 answers:
erastovalidia [21]3 years ago
7 0
Answer would be 7.5
\frac{1}{12}  \times 7.5 =  \frac{5}{8}
vesna_86 [32]3 years ago
4 0

Answer:

7 pieces, with a short piece left over (the leftover piece is 1/24 yd long).

Step-by-step explanation:

Divide the available 5/8 yd by 1/12 yd/ribbon to determine the number of pieces of 1/12 yd length could be obtained:

5

---

8

=======  This can be evaluated by inverting the 1/12 and then multiplying.

 1

-----

12

We get 5/8 times 12/1, or 60/8, which is equal to 7 4/8 pieces.

Tom was able to cut 7  1/12-yd pieces from the 5/8 yd piece, and has a 1/24  yd piece left over / remaining.



You might be interested in
I need help with this​
Ulleksa [173]
No, tahts the answer
8 0
3 years ago
The Malcolms are taking a trip. Midville is 214 miles
Juliette [100K]

Answer:

642 miles

Step-by-step explanation:

Distance of Midville from their home = 214 miles

Walesburg is 3 times as far.

How far is Walesburg from their home?

Distance of Walesburg from their home = 3 × Distance of Midville from their home

= 3 × 214 miles

= 642 miles

Distance of Walesburg from their home = 642 miles

8 0
3 years ago
Can someone please give me the answer
Serga [27]

Answer:

#1 = 234

:)

Step-by-step explanation:

7 0
3 years ago
Here is an easy puzzle:
galina1969 [7]
The answer is 
date
1                  2                 3          4             5                                         31
r1                r2               r3           r4          r5               .  .  .                  r31
1gm           2gms         3<span>gms     4gms    5gms        .   .  .                 31gms

r1+r2+ .... +r31= 31(31+1) /2=496gms  (31 rings)

he only made 5 rings

31 rings----------> 496 gms
5 rings ------------> ? = 5 x496  / 31=80 gms

</span><span> the weights of those 5 rings was 80 gms</span>
4 0
3 years ago
Which of the following is the graph of f(x) = x2 + 3x − 4?
chubhunter [2.5K]

The graph of the function for values of x ranging from -6 to +6 is shown below.

<h3>Graphing a Quadratic function</h3>

From the question, we are to graph the given quadratic function

The given quadratic function is

f(x) = x² + 3x − 4

The graph of the function for values of x ranging from -6 to +6 is shown below.

The table of values are

x       f(x)

-6      14

-5      16

-4      0

-3      -4

-2      -6

-1      -6

0      -4

1        0

2       6

3       14

4      24

5      36

6      50

Learn more on Graphing a quadratic function here: brainly.com/question/9028052

#SPJ1

8 0
2 years ago
Other questions:
  • What is the awnser to this question
    5·1 answer
  • colton's recipe makes 2 dozen brownies. his recipe calls for 7/8 cup of vegetable oil. how much oil will colton need to make 6 d
    8·1 answer
  • A groundskeeper needs grass seed to cover a circular field 290 feet in diameter
    7·2 answers
  • If y is directly proportional to x square and y equal 1/8 when x = 1/2 what is the positive value of x when y it was 9/2?
    12·1 answer
  • Reflect 4, 1 in the x-axis
    10·1 answer
  • Angles A and B are complementary. What is the value of x? 34 56 68 79
    14·2 answers
  • 60 miles/hour is how many feet/second?
    6·1 answer
  • True or false Pure tessellations can only be made with regular polygons.
    14·2 answers
  • 17. What is the slope of a line perpendicular to the line y=-x/4-1?
    8·1 answer
  • Answer asap only if you know
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!