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Gekata [30.6K]
1 year ago
13

4. Find the value of x & y from the following equation 4x+5y=90, x+y=20 a. 10, 15 b. 10, 5 c. 10, 8 d. 10, 10​

Mathematics
2 answers:
Mazyrski [523]1 year ago
6 0

Answer:

d. 10, 10

Step-by-step explanation:

4(10)+5(10) = 40 + 50 = 90

10 + 10 = 20

Hope this helps

ira [324]1 year ago
3 0

An equation is formed of two equal expressions. In the two of the given equations, the value of x and y are 10 and 10, respectively. The correct option is D.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given the two of the equation, which can be named as,

4x+5y=90   ...... equation 1

x+y=20   ............ equation 2

Solve the second equation for x,

x + y = 20

x = 20 - y ................ equation 3

In the first equation substitute the value of x from the third equation,

4x + 5y = 90

4(20 - y) + 5y = 90

Solving the equation for y,

80 - 4y + 5y = 90

y = 90 - 80

y = 10

Substitute the value of y in the second equation, to get the value of x,

x + y = 20

x + 10 = 20

x = 20 - 10

x = 10

Hence, In the two of the given equations, the value of x and y are 10 and 10, respectively.

Learn more about Equation here:

brainly.com/question/10413253

#SPJ5

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5 0
3 years ago
How many solutions does the system have?
kramer

Answer:

B. No solutions

Step-by-step explanation:

y= -3x + 9

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Rewrite the first equation below. Then, divide both sides of the second equation by 3 and write it below the first equation.

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Now look at the two equations. They are both written in the slope-intercept form, y = mx + b, where m = slope, and b = y-intercept. They have the same slope (m = -3) and different y-intercepts (9 and 3), so they are equations of two different lines, but since the slopes are the same, the lines are parallel. Since the lines never intersect, there is no solution.

Answer: No solutions

8 0
3 years ago
Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.
8_murik_8 [283]

So for this function we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0
3 years ago
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