All categories

8 months ago

Finding a percentage of a total amount: Real-world situations

Mathematics

1 answer:

Alekssandra [29.7K]8 months ago

6 0

Answer: 34.3 megabytes

Step-by-step explanation:

To find how many megabytes have been downloaded you must multiply 13.3% by 258. 13.3% can be written as the decimal 0.133

Now let's multiply

$258$ × $0.133$ =34.314

Rounded to the nearest tenth that is 34.3

You might be interested in

The sum of 4 consecutive odd number is 40. What is the greatest of the 4 numbers?

Helen [10]

13 because

13+11+9+7=40

7 0

3 years ago

In a experiment, the probability that event A occurs is 5/9, the probability that event B occurs is 5/7, and the probability tha

Ymorist [56]

Answer:

52.5% probability that A occurs given B occurs

Step-by-step explanation:

Suppose we have two events, A and B, the conditional probability formula is:

$P(A|B) = \frac{P(A \cap B)}{P(B)}$

In which

P(A|B) is the probability of A happening given that B happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(B) is the probability of B happening.

In this problem, we have that:

$P(A \cap B) = \frac{3}{8}, P(B) = \frac{5}{7}$

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{8}}{\frac{5}{7}} = 0.525$

52.5% probability that A occurs given B occurs

7 0

3 years ago

What the value of 6(2b-4} when b=5

Artist 52 [7]

Answer:

$6(2b - 4) \\ b = 5 \\ 6(2 \times 5 - 4) \\ = 6(10 - 4) \\ = 6(6) \\ = 36 \\ thank \: you$

8 0

2 years ago

Read 2 more answers

The table below shows the scores of a group of students on a 10-point quiz.Test ScoreFrequency3 54 15 16 27 28 49 310 1The mean

Katarina [22]

Explanation

Part A

We can use the formula below to find the mean.

$\text{Mean}=\sum ^{}_{}(\frac{fx}{f})$

We will then have;

$\begin{gathered} \text{Mean = }\frac{5\times3+4\times1+5\times1+6\times2+7\times2+8\times4+9\times3+10\times1}{19}=\frac{15+4+5+12+14+32+27+10}{19} \\ =\frac{119}{19}=6.2632 \end{gathered}$

Mean = 6.2632

Part B

Since the data set is odd.

$\begin{gathered} \text{Median}=\frac{(n+1)}{2}^{th}\text{observation} \\ =\text{Value of }\frac{\text{(19+1)}}{2}^{th}\text{observation} \\ =\text{value of 10th observation} \end{gathered}$

Answer: From the column of cumulative frequency cf, the median is 7

5 0

1 year ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.