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Law Incorporation [45]
2 years ago
6

If the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

how many books on average does each student have?
Mathematics
1 answer:
Whitepunk [10]2 years ago
5 0

The number of books taken by each student is 6.

<h3>What is an average?</h3>

Average is defined as the ratio of the sum of the number of the data sets to the total number of the data. The average actually determines the middle value of the data.

Given that the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

The average is calculated by dividing the sum of the total number of items by the total counts of the items.

Average = 14400 / 2400

Average = 6

Therefore, the number of books taken by each student is 6.

To know more about an average follow

brainly.com/question/20118982

#SPJ2

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I have 7200 bags of snickers. If the rest is Hershey’s and Twix is 2/3 of snickers, how many Hershey’s are there?
AveGali [126]

Answer:

Step-by-step explanation:

You have 7,200 bags of snickers

Twix is 2/3 that of snickers

Hershey's is ?

First you need to find out how much Twix you have.

You will need to multiply as a fraction: 2/3*7,200/1 (2 over 3 multiplied by 7,200 over 1)

Next multiply the two numerators together (numerators are the numbers on top of a fraction and the numbers on the bottom of the fraction are called denominators)

2 * 7,200 = 14,400

Next multiply the denominators together:

3 * 1 = 3

So now your fraction is 14,400/3 (14,400 over 3)

Now divide the denominator into the numerator:

14,400 divided by 3 = 4,800

So 2/3 of the 7,200 bags of Snickers equals 4,800 Twix

Now take away the Twix from the Snickers

7,200 - 4,800 = 2,400

So now all up you have:

7,200 bags of snickers

4,800 bags of Twix

2,400 bags of hershey's

=)

4 0
2 years ago
A car travels 279 miles in 4 1/2 hours. How many miles would the car travel<br> in 12 hours? *
Liono4ka [1.6K]

Answer:

744 miles in 12 hours.

Step-by-step explanation:

MATH

4 0
2 years ago
Please help me! ASAP!!!!!
Greeley [361]

Answer:

x=36

Step-by-step explanation:

17+3 =20

now we have :

x+4

___         = 20

  2

20*2= 40

x+4=40

x=36

hopes this helps

4 0
2 years ago
Please help me,ASAP​
pav-90 [236]

Answer:

b. They can both be 90 degree angles

c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees

d. should be always

e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)

Step-by-step explanation:

8 0
3 years ago
Which of the following is not one of the 8th roots of unity?
Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1.  Since z=1=1+0\cdot i, then

Rez=1,\\ \\Im z=0

and

|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.

This gives you \varphi=0.

Thus,

z=1\cdot(\cos 0+i\sin 0).

2. The 8th roots can be calculated using following formula:

\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.

Now

at k=0,  z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;

at k=1,  z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=2,  z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;

at k=3,  z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=4,  z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;

at k=5,  z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

at k=6,  z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;

at k=7,  z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

The 8th roots are

\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.

Option C is icncorrect.

5 0
2 years ago
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