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Law Incorporation [45]
2 years ago
6

If the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

how many books on average does each student have?
Mathematics
1 answer:
Whitepunk [10]2 years ago
5 0

The number of books taken by each student is 6.

<h3>What is an average?</h3>

Average is defined as the ratio of the sum of the number of the data sets to the total number of the data. The average actually determines the middle value of the data.

Given that the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

The average is calculated by dividing the sum of the total number of items by the total counts of the items.

Average = 14400 / 2400

Average = 6

Therefore, the number of books taken by each student is 6.

To know more about an average follow

brainly.com/question/20118982

#SPJ2

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The answer is 23.

11+23=34

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Consider the following recursively defined sequence a1 = 2 an = an-1 – 3 for n &gt;= 2 In this question, we will prove that an =
Rudiy27

Answer with Step-by-step explanation:

We are given that

a_1=2

a_n=a_{n-1}-3 for for  [tex]n\geq2

We have to prove that a_n=-3n+5 for all n equal and greater than 1

proof: Let P(n)=a_n=-3n+5 for all n equals to and greater than 1

We prove that for all n there exists Z,if n greater and equals to zero

Base case : The base case is n=1

Substitute n=1 then we get

P(1)=-3(1)+5=2

This is true for n=1

Induction step : suppose that P(n) is true for n=k where k greater than 1

Then P(k)=-3k+5

Now, we shall prove that for n=k+1, P(n) is true for n=k+1

P(k+1)=-3(k+1)+5

P(k+1)=-3k-3+5=-3k+5-3

P(k+1)=a_k-3

a_{k+1}=a_k-3

We are given that a_n=a_{n-1}-3 for n equal to and greater than 2

Therefore, P(n) is true for n=k+1

Hence, P(n)=-3n+5 for all n equal and greater than 1

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