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olga2289 [7]
3 years ago
15

Find the values of x and y. Write your answer in simplest form.

Mathematics
2 answers:
agasfer [191]3 years ago
5 0

Answer:

y = 6√3 and x = 6

Step-by-step explanation:

this is a 30-60-90 triangle.  The side opposite the 30° angle corresponds to the side of length 1  in the most basic 30-60-90 triangle; the side opp. 60° to the side of length √3; and the hyp. to the side of length 2.

To find y, write and solve an equation of ratios, as follows:

adj side           adj side      (adjacent to the 30° angle)

    y                       √3

 hypo               hypo    then (cross multiplying):  2y = 12√3, and

    12                     2       y = 6√3

If the hypo here is 12 and the adj side (y) is 6√3, then we can use the Pyth. Theorem to find the third side (x):

[12]² = [6√3]² - x²  ↔ 144 = 36(3) - x²   ↔  36 = x².  So x = 6 here.

Lyrx [107]3 years ago
5 0

Answer:

x = 6

y ≈ 10. 40

Step-by-step explanation:

Using the SOHCAHTOA principle we can solve for x and y since the angle is known and it is a right angle triangle.

hypotenuse = 12

adjacent = x

opposite = y

cos 60° = adjacent/hypotenus

cos 60° = x/12

cross multiply

x = 12 cos 60°

x = 12 × 0.5

x = 6

Finding y

sin 60° = opposite/hypotenuse

sin 60° = y/12

cross multiply

y = 12 sin 60°

y  = 12 × 0.8660254038

y =  10.392304845

y ≈ 10. 40

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What is the product
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Answer:

The product of given matrix is AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}

Step-by-step explanation:

Given : Two matrix

A=\begin{pmatrix}3&6&1\\ 2&4&0\\ 0&6&2\end{pmatrix}

and B=\begin{pmatrix}2\\ \:0\\ \:1\end{pmatrix}

We have to find the product of given matrix

AB=\begin{pmatrix}3&6&1\\ 2&4&0\\ 0&6&2\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}

Multiply the rows of first matrix by the columns of second matrix , we have,

\begin{pmatrix}3&6&1\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=3\cdot \:2+6\cdot \:0+1\cdot \:1

\begin{pmatrix}2&4&0\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=2\cdot \:2+4\cdot \:0+0\cdot \:1

\begin{pmatrix}0&6&2\end{pmatrix}\begin{pmatrix}2\\ 0\\ 1\end{pmatrix}=0\cdot \:2+6\cdot \:0+2\cdot \:1

=\begin{pmatrix}3\cdot \:2+6\cdot \:0+1\cdot \:1\\ 2\cdot \:2+4\cdot \:0+0\cdot \:1\\ 0\cdot \:2+6\cdot \:0+2\cdot \:1\end{pmatrix}

On , simplifying , we get,

AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}

Thus, the product of given matrix is AB=\begin{pmatrix}7\\ 4\\ 2\end{pmatrix}

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Step-by-step explanation:

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