Answer:
I cant answer it because you cant copy it it doesnt allow me
The area of the sector (As) of a circle may be calculated by the formula,
As = (a / 360) x π x r²
where a is the measure of angle in degrees and r is the radius. Substituting the known values,
As = (18 / 360) x 3.14 x (4²) = 2.512
Thus, the area of the sector is approximately 2.512 squared units.
Hyp^2 = leg1^2 + leg2^2
hyp^2 -leg1^2 = leg2^2
17^2 - 8^2 = leg2^2
leg2^2 = 289 -64
leg2^2 = 225
leg2 = 15
The simplest form of 204/72
=17/6
∠A=6x−18 ∘ start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 6, x, minus, 18, degrees, end color #1
denpristay [2]
Using the properties of alternate angles, the value of x = 8 and ∠ A = 30
<h3>What are Alternate Angles?</h3>
A transversal that crosses two parallel lines produces alternate exterior angles. They form two pairs (four total angles) of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal.
For the given question,
∠A=6x−18
∠B=14x+38
As, both parallel lines are intersected by a transversal,
the value of angle ∠A and ∠180 - B is same as they are alternate angles,
⇒ 6x−18 = 180 - 14x - 38
⇒ 6x + 14x = 142 + 18
⇒ 20x = 160
⇒ x = 8
∠A = 6x−18
⇒ ∠ A = 30
To learn more abut alternate angles from given link
brainly.com/question/26167358
#SPJ13
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