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ololo11 [35]
2 years ago
6

What is the slope intercept form written in equation form of this graph?

Mathematics
1 answer:
serg [7]2 years ago
4 0
Y=2x+4
the y intercept is 4 and the slope is 2/1
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Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?
andrew11 [14]
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
4 0
3 years ago
Describe how the graph of the function g(x) = -5x²-2 is related to the graph of
zhenek [66]

Answer:

(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units

3 0
1 year ago
(PLSSSS HELP, MY FATE IS IN YOUR HANDS) Determine which three out of the six points shown below are a solution to the equation x
alexandr402 [8]

Answer:

The required points are -

(-2,8), (7,5), (1,7)

4 0
2 years ago
Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two
Damm [24]

Answer:

7

Step-by-step explanation:

Let S be the set of all graphs having vertex set  \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

8 0
2 years ago
Do any of them you know
snow_tiger [21]

Answer:

I believe I am correct.

1: slope

2: linear equation

3: y-intercept

4: slope-intercept form

5: y-intercept is (0,6) the slope is -2

6: y-intercept is (0,3.4) the slope is 10/6

7: y-intercept is (0,4) the slope is -4/16

Hope this works for you Jack Jiang.

5 0
3 years ago
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