Answer: The possible genotype for their child is Hh. All the children will be heterozygous for Huntington (Hh).
The possible phenotype for their child is Huntington disease.
Explanation: If H represents the trait for Huntington and h represents normal trait; and if Huntington trait (H) is dominant over normal trait (h), therefore the genotype of the mother who is homozygous for Huntington disease is HH and the genotype of the man who is homozygous normal is hh.
A cross between the man and woman will produce offsprings who are all heterozygous for Huntington disease Hh. Phenotypically, the offsprings will manifest as Huntington disease.
See the attached punnet square for more information
Answer: hope this helps
Explanation:
Aerobic bacteria use oxygen, which is added mechanically, to break down wastewater contaminants, converting it into energy. Bacteria use this energy to grow and reproduce. Anaerobic bacteria obtain oxygen from their food source. As anaerobic bacteria break down sludge, they produce methane gas. This methane gas can be used as an alternative energy source, called biogas, to fuel the wastewater treatment process.
Soot is mainly composed of carbon. The black particles is ALL carbon because of the incomplete combustion of the hydrocarbons. Therefore, your answer is B, black carbon.
Answer:
i think its b.
Explanation:
bc they arnt autotrops they dont undergo anything.