All categories

1 year ago

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Mathematics

2 answers:

Delicious77 [7]1 year ago

4 0

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.

You might be interested in

Dean selects Teakwood stones

Gelneren [198K]

Answer:

You didnt give us data to use

for example TEAKWOOD IS 3 METER LONG AND PATH 10 HOW LONG IS BUCKSKIN

Step-by-step explanation:

8 0

3 years ago

At the movies, you order 3 boxes of popcorn and a bottle of water. The cost of the bottle of water is $1.75. Your total cost is

maksim [4K]

3w = $9.25 would be the equation in this case. In order to solve it, you must divide $9.25 by 3. $9.25 / 3 = $3.83 (repeating bar over the second 3). The cost of one box of popcorn is $3.83.

4 0

2 years ago

Read 2 more answers

Select all of the terms that are "like." xy2 2xy x2 -xy 2x2y xy

Alinara [238K]

Xy2 and 2xy are the only ones with common factors

7 0

3 years ago

Read 2 more answers

Translate the sentence into an equation Twice the difference of a number and 9 is equal to 5use the variable w for the unknown n

TEA [102]

Let w the unknown number. Then, you have

$\begin{gathered} 2(w-9)\rightarrow\text{ Twice the difference of a number and 9} \\ 2(w-9)=5\rightarrow\text{Twice the difference of a number and 9 is equal to 5} \end{gathered}$

3 0

1 year ago

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago