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3 years ago

Find the mid point of (2,-2)(12,,-6)

Mathematics

2 answers:

crimeas [40]3 years ago

6 0

Answer:

(7,-4)

Step-by-step explanation:

Oksana_A [137]3 years ago

4 0

Answer:

(7, -4)

Step-by-step explanation:

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Given tu ij find the length of hj

Vladimir79 [104]

that doesnt make sense

4 0

2 years ago

an orange is divided into 6 equal wedges Jody eats 1 wedge then she eats 3 more wedges how much of the orange did Jody eat

chubhunter [2.5K]

Out of 6 wedges, Jody eats 4 wedges obviously so he eats 4/6 of the orange or to make it simple 2/3 of it

4 0

3 years ago

Read 2 more answers

Simplify: 18q2−45q+25/9q2−25.

Svet_ta [14]

Answer:

$\frac{(6q-5)}{(3q+5)}$

Step-by-step explanation:

Given: $\frac{18q^{2}-45q+25 }{9q^{2}-25 }$

Factorizing the numerator and the denominator, we have:

18 $q^{2}$ - 45q + 25 = 18 $q^{2}$ - 30q - 15q + 25

= (3q - 5)(6q - 5)

and

9 $q^{2}$ - 25 = (3q - 5)(3q + 5)

So that,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}$

= $\frac{(6q-5)}{(3q+5)}$

Therefore,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(6q-5)}{(3q+5)}$

5 0

3 years ago

Explain the full answer

Vilka [71]

Rememer you can do anything to an equaiton as long as you do it to both sides

and the erased answer is correct

10=-6.5+n
add 6.5 both sides
10+6.5=6.5-6.5+n
16.5=0+n
16.5=n

3 0

3 years ago

Given circle X with radius 5 units and chord AB with length 8 units, what is the

kvv77 [185]

Answer: The correct option is (B) 3.

Step-by-step explanation: We are given a circle X with radius 5 units and chord AB with length 8 units.

We are to find the length of segment XC that bisects chord.

We know that the line segment drawn from the center of a circle to the midpoint of a chord is perpendicular to the chord.

So, in the given circle X, the segment XC is perpendicular to chord AB. Then, triangle XCB will be a right angled triangle with hypotenuse XB.

Since XC bisects AB, so the length of BC will be

$BC=\dfrac{AB}{2}=\dfrac{8}{2}=4~\textup{units}.$

And, radius, XB = 5 units.

Using Pythagoras theorem in triangle XCB, we have

$XB^2=XC^2+BC^2\\\\\Rightarrow XC^2=XB^2-BC^2\\\\\Rightarrow XC^@=5^2-4^2\\\\\Rightarrow XC^2=9\\\\\Rightarrow XC^2=3^2\\\\\Rightarrow XC=3.$

Thus, the length of the segment XC is 3 units.

Option (B) is CORRECT.

3 0

3 years ago