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4 years ago

13

A. A plane takes off, gaining altitude at a constant rate. When it

1 answer:

riadik2000 [5.3K]4 years ago

8 0

Answer: A

Step-by-step explanation: Because it’s correct and pls give me brainliest

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I need help on my other question and quick!!

ira [324]

Answer:

wait which one?

have u posted it?

Step-by-step explanation:

3 0

3 years ago

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Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes a

Luden [163]

$1\frac{1}{8} = \frac{9}{8} = 1.125, 
 \\ 75*1.125= 84.375$

84.375 is the profit ALREADY made, so now subtract that from 180 dollars to get
95.625 $ needed, now divide by amount of profit per box...

Answer should be 85 boxes

4 0

3 years ago

ou buy a gallon of milk that costs $3.50. The milk is discounted for 10% off. You also have to pay tax of 6.25% on the discounte

Alchen [17]

Answer:

3.35.

Step-by-step explanation:

very simple!

3 0

3 years ago

A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl

lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

$m=\frac{y_2-y_1}{x_2-x_1 }$

<u>Slope of AB</u>

$m_{AB}=\frac{8-5}{1--5}$

$\Rightarrow m_{AB}=\frac{8-5}{1+5}$

$\Rightarrow m_{AB}=\frac{3}{6}$

$\Rightarrow m_{AB}=\frac{1}{2}$

<u>Slope of BC</u>

$m_{BC}=\frac{2-8}{4-1}$

$\Rightarrow m_{BC}=\frac{-6}{3}$

$\Rightarrow m_{BC}=-2$

<u>Slope of CD</u>

$m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-4}{-6}$

$\Rightarrow m_{CD}=\frac{2}{3}$

<u>Slope of AD</u>

$m_{AD}=\frac{-2-5}{-2--5}$

$\Rightarrow m_{AD}=\frac{-2-5}{-2+5}$

$\Rightarrow m_{AD}=\frac{-7}{3}$

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

$m_{AD} = \frac{-7}{3} \neq m_{BC}=-2$

$m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}$

<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

$m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1$

$m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1$

Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle

6 0

3 years ago

Aman and Prakash coloured an entire Harry Potter Colouring Book together. The book had 75 pages. Aman coloured 60% of the pages.

tia_tia [17]

Answer:

A) 30 pages

Step-by-step explanation:

No of pages = 75

Aman coloured 60 % of the pages= 75 *60/100= 45

Prakash coloured 75 - 45 = 30 pages

8 0

3 years ago

Read 2 more answers