To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:
all work is shown / pictured
Answer:
0
Step-by-step explanation:
Answer:
Option (4)
Step-by-step explanation:
In the picture attached,
m∠NLM = m∠LKN = 90°
In two similar triangles ΔLKN and ΔMKL,
By the property of similar triangles,
"Ratio of the corresponding sides of the similar triangles are proportional".
By substituting the values given,
Therefore, Option (4) will be the answer.
Answer:
x = 4
, y = 6
Step-by-step explanation:
Solve the following system:
{x + 3 y = 22 | (equation 1)
2 x - y = 2 | (equation 2)
Swap equation 1 with equation 2:
{2 x - y = 2 | (equation 1)
x + 3 y = 22 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x - y = 2 | (equation 1)
0 x+(7 y)/2 = 21 | (equation 2)
Multiply equation 2 by 2/7:
{2 x - y = 2 | (equation 1)
0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{2 x+0 y = 8 | (equation 1)
0 x+y = 6 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 4
, y = 6
