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Kruka [31]
3 years ago
12

Brandy deposits $200 each year into her savings account. It earns 3% annual interest compounded annually. About how much will be

in her account at the end of 3 years?
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0
Hello! 3% interest is earned annually and $200 is added per year. 3% is 0.03 in decimal form. Let's add 1 to that number. 1 + 0.03 is 1.03. Let's multiply that by 200. 200 * 1.03 is 206. That's the amount after 1 year. Add 200 to that amount. 206 + 200 is 406. Multiply that amount by 1.03. 406 * 1.03 is 418.18. That is the amount after the second year. Now, add 200 to that amount. 418.18 + 200 is 618.18. Multiply that amount by 1.03. 418.18 * 1.03 is 636.7254 or 637 when rounded to the nearest whole number. Keep in mind that we add 200 each year and then multiply the amount by 103% (1.03) after that. There. Brandy will have about $637 after 3 years. The answer is C: $637.
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What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet.
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The maximum height of the projectile will be 226 feet that is, as per question, the option c.

A quadratic equation , y = ax²+bx+c  (equation 1)

given, axis of symmetry is

x = \frac{b}{2a}

As per the question:

The path of the projectile is modeled using the equation :

h(t) = -16t²+48t+190  (equation 2)

h(t) = height after t time.

comparing equation 1 and equation 2, we get

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further, t = \frac{48}{2(-16)}

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Substituting the found value in equation 2, we get

h(1.5) = -16(1.5)²+48(1.5)+190

h(1.5) = -36+72+190

h(1.5) = 226ft.

Thus, the maximum height of the projectile at 1.5 sec is, 226 feet.

Note that the full question is:

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.

What is the maximum height of the projectile?

A. 82 feet

B. 190 feet

C. 226 feet

D. 250 feet

To learn more about velocity: brainly.com/question/25749514

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