Answer:
Slope: 1/3; Y-iintercept: 4 y=1/3x+4
Slope: -2; Y-intercept: 4 y=-2x
Step-by-step explanation:
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Answer:
The answer is 1811.6, but rounded 1812.
The soluton to the problem is as follows:
d/dx (cot⁻¹(x)) = −1/(x²+1)
d/dx (cot⁻¹ √[(1+cos(3x))/(1−cos(3x))])
<span>
= −1/[(1+cos(3x))/(1−cos(3x)) + 1] * d/dx √[(1+cos(3x))/(1−cos(3x))] </span>
<span>
= −(1−cos(3x))/2 * 1/2 [(1+cos(3x))/(1−cos(3x))]^(−1/2) * d/dx (1+cos(3x))/(1−cos(3x)) </span>
<span>
= −1/4 (1−cos(3x))^(3/2)/√(1+cos(3x)) * [−3sin(3x)(1−cos(3x)) − (1+cos(3x))(3sin(3x))]/(1−cos(3x))^2 </span>
<span>
= −1/4 (1−cos(3x))^(3/2)/√(1+cos(3x)) * (−6sin(3x))/(1−cos(3x))^2 </span>
<span>
= 3 sin(3x) / (2 √[(1−cos(3x))(1+cos(3x))]) </span>
<span>
= 3 sin(3x) / (2 √(1−cos²(3x))) </span>
<span>
= 3 sin(3x) / (2 √(sin²(3x))) </span>
<span>
= 3 sin(3x) / (2 |sin(3x)|)
</span>
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Answer:
uhm
Step-by-step explanation:
Answer:
The possibility that John And sue both miss their shots = 0.39
Step-by-step explanation:
John makes 35% of his free throw shots = 0.35
The probability of John missing his shot = 0.65
Sue makes 40% of her free throw shot = 0.4
The probability of Sue missing his shot = 0.6
The possibility that John And sue both miss their shots = 0.65 (0.6)
= 0.39