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4 years ago

7

What is 10^4 in standard notation

2 answers:

NARA [144]4 years ago

7 0

Answer:

10,000

Step-by-step explanation:

Standard notation is just the normal way of writing things. 10 x 10 x 10 x 10 = 10,000.

frutty [35]4 years ago

6 0

ANSWER : 10,000

BECAUSE: 10 x 10 x 10 x 10 = 10,000

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A boat travelled 336 km downstream with the current. The trip downstream took 12 hours.

miskamm [114]

Answer:

We know the distance (d) equation in terms of rate (r) and time (t) as:

d=rt

Step-by-step explanation:

We have given d=336 km and t= 12 hours, so we have: 336 km = 12t <-- this is our equation.

Divide each side by 12 to solve for t:

12t/12=336/12

t= 28 km/ hour

5 0

3 years ago

the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare

ddd [48]

The length of the line segment AB where $A(x_A;\ y_A)$ and $B(x_B;\ y_B)$

$|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

We have: $A(1;\ 6);\ B(11;-4)$

subtitute

$|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1$

Answer: b. 14.1

3 0

3 years ago

108 = 9r<br> I need help with this plz

kondor19780726 [428]

Answer:

r = 12

Step-by-step explanation:

108 = 9r | Given expression

12 = r | Divide both sides by 9. 108 becomes 12 and 9r becomes r.

3 0

3 years ago

Read 2 more answers

Hey guys, I'm relearning some Algebra and was confused about this problem. In the equation, the problem was divided by 3. This m

spayn [35]

Answer and Step-by-step explanation:

The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:

-18x² - 15x + 3 = 0

into

(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0

6x² + 5x - 1 = 0

And that gives the "swapped signs".

4 0

3 years ago

Read 2 more answers

Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

8 0

4 years ago