Answer:
10 or -10,
Read the explanation
Step-by-step explanation:
Rewrite this problem as a numerical expression. As per the wording of this problem, there can be two expressions derived.
1. 
2. 
Simplify, remember the order of operations. The order of operations is the sequence by which one is supposed to perform operations in a numerical expression. This order is the following:
1. Parenthesis
2. Exponents
3. Multiplication or division
4. Addition or Subtraction
Use this sequence when simplifying and solving the expression:
Expression 1
Expression 2
Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.
For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- He makes 90% of the free throws, hence
.
- He is going to shoot 3 free throws, hence
.
The probability that he makes exactly 1 is P(X = 1), hence:
0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
48
Step-by-step explanation:
because 20% of 240 is 48.
To figure this out you first find the difference between -18 and 60, which is 78 you then just divide, 78/4.5 which is approximately 17.55 mins or 17.6 rounded.
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
