The figure is missing so I attached a helping figure
Answer:
Line segment ST is congruent to line segment UT
Step-by-step explanation:
From the attached figure
∵ ST and UT are tangents to circle K at points S and U
∵ SK and UK are radii in the circle K
- The tangent is perpendicular to the radius at the point of tangent
∴ ST ⊥ KS ⇒ at point S
∴ m∠KST = 90°
∴ UT ⊥ KU ⇒ at point U
∴ m∠KUT = 90°
∴ m∠KST = m∠KUT
In the two triangles KST and KUT
∵ KS = KU ⇒ radii
∵ m∠KST = m∠KUT ⇒ proved
∵ KT is a common side in the two triangles
- That means the two triangles are congruent by HL postulate
of congruence (hypotenuse and leg of right triangle)
∴ Δ KST ≅ KUT ⇒ HL postulate of congruence
- By using the result of congruence
∴ ST = UT
Line segment ST is congruent to line segment UT
Profit = paid - supplies
Plug in the given values. We are finding out how much money he needs per room, if he is doing 4 rooms, and subtracting the supplies: 300 = 4n - 4*32.50
Simplify: 300 = 4n - 130
Add 130 to each side. 430 = 4n
Divide by 4 on each side: 107.50= n
300 = 4(107.50) - 130? True
This tells us he must be paid $107.50 to make $300 exactly. Anything larger than $107.51 and up will make more than $300.
Answer: a: 5
b: 12
Step-by-step explanation:
<h3>
Answer: Choice C, 2/3</h3>
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Work Shown:
A = # of candies that are not green
A = (# of red)+(# of yellow)+(# of blue)
A = 25+15+20
A = 60
B = # of candies total
B = (# of red)+(# of green)+(# of yellow)+(# of blue)
B = 25+30+15+20
B = 90
P(not green) = probability of selecting candy that is not green
P(not green) = (# of candies not green)/(# of candies total)
P(not green) = A/B
P(not green) = 60/90
P(not green) = (2*30)/(3*30)
P(not green) = 2/3
Answer:
It would be y=3(x+2).
Step-by-step explanation:
(This is the explanation you write.)
If you simplify the equation it is y=3x+6. For line A the y-intercept is 6 and the slope is 3.
