The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
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Answer:
h = 6
Step-by-step explanation:
Given the 2 equations
- 3x + 4y = - 30 → (1)
9x + 5y = 39 → (2)
We require the value of the x- coordinate at the point of intersection, thus require to eliminate the y- term from the equations
Multiply (1) by 5 and (2) by - 4
- 15x + 20y = - 150 → (3)
- 36x - 20y = - 156 → (4)
Add (3) and (4) term by term thus eliminating y
- 51x = - 306 ( divide both sides by - 51 )
x = h = 6
Consecutive numbers can be written as such:
n + (n + 1) = 73
Open the parentheses and simplify:
2n + 1 = 73
Subtract 1 from both sides:
2n = 72
Divide both sides by 2:
n = 36
The numbers are 36 and 37
