Step-by-step explanation:
Given the line y-1 = 1(x+2), in order to know the line that is perpendicular to the given line, we will first find the slope of the known line.
The standard form of equation of a line is expressed as y = mx+c
m is the slope
c is the intercept
Rewrite the equation given
y-1 = 1(x+2)
y-1 = x+2
y = x+2+1
y = x+3
Comparing to the standard form, the slope m = 1.
For two lines to be perpendicular, the product of their slope must be -1 i.e mM = -1
Substitute
1(M) = -1
M = -1
For us to know the line that is perpendicular to the given line, its slope must be -1.
<em>Since none of the equation has a slope of -1, hence none of the lines are perpendicular to the line y - 1= 1(x+2).</em>
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BY taking the square root you can find each of them as follows:
1. sqrt(144) = 12
2. sqrt(25/289) = 5/17
Number 1 is x=8!!
2 is pretty confusing so I hope someone else can answer two as I have answered 1!
If we use similar triangles ( as shown in the attachment ) we will see that the line CM is also 1/4 *( yC-yD)= 1/4*(2+2) = 1/4*4 =1
Answer: y-value of that point is A)
y=1.
