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Mnenie [13.5K]
3 years ago
12

9. An air conditioning system can circulate 350 cubic feet of air

Mathematics
2 answers:
Tanya [424]3 years ago
8 0

An air conditioning system can circulate 350 cubic feet of air

per minute. How many cubic yards of air can it circulate per

minute?

About 13.0 cubic yards

kramer3 years ago
3 0

Answer:

350 cubic feet of air per minute would be 13.0 cubic yards.

Step-by-step explanation:

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What is the missing side and what is the answer rounded to the nearest tenth?
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The missing side is 17 and rounded it is 20

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3 years ago
How would the expression x^3+64 be rewritten using sum off cubes
Mamont248 [21]
\bf \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
\boxed{64=4^3}\qquad x^3+64\implies x^3+4^3\implies (x+4)(x^2-x4+4^2)
\\\\\\
(x+4)(x^2-4x+16)
8 0
3 years ago
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Simplify<br>(a + 2b +30) - (40+36-5a)​
Crazy boy [7]

Step-by-step explanation:

  • (a+2b+30)-(40+36-5a)
  • a+2b+30-40-36+5a
  • 6a+2b-46

hope it helps.

3 0
3 years ago
Can anyone help me pls. Show your work.
nekit [7.7K]

Answer:Do you have a pic of the map? It would  make it easier to solve if I could see the map. Its basic area. A=base times height. If the park is 50 m long and is a square, you would do 50 times 50=2500

tep-by-step explanation:

4 0
3 years ago
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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
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