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Pepsi [2]
3 years ago
9

1.)

Chemistry
1 answer:
Burka [1]3 years ago
6 0
1) acidic because the presence of H+ ions indicates an acid eg. H2SO4

2) Base - OH- ions indicate alkaline eg. LiOH
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The negatively charged particles of an atom are the
posledela

Answer:

Electron: A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.

Explanation:

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3 years ago
PWEASE REVIEW ME AND ME MATES TEEF
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So the first one is yellow and the other one is white
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Which cell structure is correctly paired with its primary function?
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Answer:

C

Explanation:

Mitochondria provides energy (ATP) for cells to use

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4 years ago
Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering. B) invertebrates
tensa zangetsu [6.8K]

Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering.

The picture shows flowering plants that are using seeds, flowers or fruits and they are called flowering plant .

So the answer here is A) flowering.

Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering.

7 0
4 years ago
Read 2 more answers
The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
4 years ago
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